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3 years ago

while monitoring dopple radar, what are two things meterologists look for that could indicate the formation of a tornado

1 answer:

5 0

Answer: So when a Doppler radar detects a large rotating updraft that occurs inside a supercell, it is called a mesocyclone. It has smaller, tighter rotation than a mesocyclone.

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Sub-atomic particles like negatively charged electrons, positively charged

leonid [27]

Answer:

neutral

Explanation:

There are three basic subatomic particles. These are;

Protons (positively charged)
Electrons (negatively charged)
Neutrons (neutral)

A neutron has no charge unlike the proton and the electron. It is present in the nucleus and contributes to the mass of the atom.

8 0

2 years ago

Difference between practical work inside and outside laboratory

arsen [322]

Practical work refers to the art of conducting experiments in order to answer certain research questions.

<h3>What is practical work?</h3>

In science, practical work refers to the art of conducting experiments in order to answer certain research questions. This could occur in a laboratory under controlled conditions or in the field.

In the physical sciences, most of the practical work is conducted in the laboratory under controlled conditions. However, some experiments in the biological sciences and most experiments in the social sciences are conducted outside the laboratory.

Learn more about experiments:brainly.com/question/11256472

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5 0

2 years ago

Stearic acid (C18H36O2) is a fatty acid, a molecule with a long hydrocarbon chain and an organic acid group (COOH) at the end. I

Paha777 [63]

Answer:

There is 9671 Kj of heat released

Explanation:

Step 1: The balanced equation:

C18H36O2(s) + 26O2(g) --> 18CO2(g)+18H2O(g)

This means for 1 mole of C18H36O2 consumed there is 26 moles of O2 needed to produce 18 moles of CO2 and 18 moles of H2O.

Step 2: Calculate the heat of combustion

ΔH (combustion) = [18*(ΔHf of CO2) + 18*(ΔHf of H2O)] - [1*(ΔHf of C18H36O2) + 26*(ΔHf of O2)]

ΔH (combustion) = [18*(-394 kJ/mol) + 18*(-242 kJ/mol)] - [1*(-948 kJ/mol) + 26*(0 kJ/mol)]

ΔH (combustion) = [(-7092 kJ/mol) + (-4356 kJ/mol)] - (-948 kJ/mol)

= -10500 kJ/mol

ΔH (combustion) = heat released / number of moles of stearic acid

Step 3: Calculate moles of stearic acid

moles of stearic acid = mass / Molar mass of stearic acid

moles of stearic acid = 262g / 284.48 g/mole = 0.921 moles

Step 4: Calculate moles of oxygen

moles of O2 = 914.5 / 32g/mole

moles of O2 = 28.578125 moles

Stearic acid is the limiting reactant: it will completely react

There will react 26*0.921 mole = 23.946 mole of O2

This means there will remain 4.63 moles of O2

Step 5: Calculate heat released

q = (ΔH combustion) * (moles of stearic acid) = (-10500 kJ/mol) * (0.921 moles) = 9671 Kj

There is 9671 Kj of heat released

6 0

3 years ago

A 23.6 ml of slat water has a mass of 26.47 grams. calculate its density.

bija089 [108]

The density is 1.12161 g/ml

7 0

3 years ago

A potted plant is placed under a grow lamp, which provides 6,400 J of energy to the plant and the soil over the course of an hou

STatiana [176]

Answer:

823.7g

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Using the information given in this question as follows:

Q = 6,400 J

m = ?

c of soil = 0.840 J/g°C

∆T = 9.25°C

Using Q = mc∆T

m = Q ÷ c∆T

m = 6,400 ÷ (0.840 × 9.25)

m = 6400 ÷ 7.77

m = 823.7g

8 0

3 years ago

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