Answer:
yes
Explanation:
its safe trust me i have tried it
Answer:
There are required 70.1 years for the activity of a sample of cesium-137 to fall to 20.0 percent of its original value
Explanation:
The radioactive decay follows always first-order kinetics where its general law is:
Ln[A] = -Kt + ln[A]₀
<em>Where [A] is actual concentration of the atom, k is rate constant, t is time and [A]₀ is initial concentration.</em>
We can find rate constant from half-life as follows:
<em>Rate constant:</em>
t(1/2) = ln 2 / K
As half-life of Cesium-137 is 30.2 years:
30.2 years = ln 2 / K
<em>K = 0.02295 years⁻¹</em>
Replacing this result and with the given data of the problem:
Ln[A] = -Kt + ln[A]₀
Ln[A] = -0.02295 years⁻¹* t + ln[A]₀
Ln ([A] / [A₀]) = -0.02295 years⁻¹* t
<em>As you want time when [A] is 20% of [A]₀, [A] / [A]₀ = 0.2:</em>
Ln (0.2) = -0.02295 years⁻¹* t
70.1 years = t
<h3>There are required 70.1 years for the activity of a sample of cesium-137 to fall to 20.0 percent of its original value</h3>
Answer: The answer is A, A new element or different atom formed from the original two.
Hope this helps! :D
-<em>TanqR</em>
Inorganic compounds make ionic bonds.
Answer:
Alpha particles are energetic (fast) helium nuclei, beta particles are smaller and have half the charge, being energetic electrons (or positrons) only the gamma particles are photons, i.e., they are not massive particles at all, they are a form of electromagnetic radiation, a form more energetic than X-rays
