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Paladinen [302]
3 years ago
8

How does Electromagnetic Energy Travel?

Physics
1 answer:
alisha [4.7K]3 years ago
6 0

Answer:

Perpendicular to the electric field and magnetic field

Explanation:

Electromagnetic waves are transverse waves composed by the perpendicular oscillating electric and magnetic fields.

EM waves have both Electrical and magnetic features.

they travel in the velocity of light (3*10⁸ ms⁻¹)

they does not require any media to travel. It has two perpendicular electric field and the magnetic field which are perpendicular to each other

They travel perpendicular to each of those electric and magnetic fields.  

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Can anyone please tell me the properties of image formed in a spherical mirror?
notsponge [240]

Answer:

The two rays, CY and DM are diverging rays and when extended behind the mirror, they appear to intersect each other at point M'. Therefore, the properties of the images formed here are formed behind the mirror, between the pole and principal focus (f), the images are diminished and are virtual and erect.

Explanation:

<h2>Spherical Mirrors</h2>

  • There are two kinds of spherical mirrors, concave and convex.

  • The focal point (F) of a concave mirror is the point at which a parallel beam of light is "focussed" after reflection in the mirror. ...

  • The focal length (f) and radius of curvature (R) are defined in the diagram at the right.

<h3>hope it helps and thanks for following </h3><h2>please give brainliest </h2>
6 0
3 years ago
Read 2 more answers
A charge q produces an electric field of strength 4E at a distance of d away. Determine the electric field strength at a distanc
gizmo_the_mogwai [7]

Answer:

c.) 36E

Explanation:

The magnitude of the electric field is given by the expression

E=k \frac{q}{d^2} (1)

where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.

In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as

4E = k\frac{q}{d^2}

Now we want to determine the electric field at a distance of d'=\frac{1}{3}d away. Substituting into (1), we find

E' = k \frac{q}{d'^2}=k \frac{q}{(\frac{1}{3}d)^2}=9 k \frac{q}{d^2} (2)

We also know that

4E = k\frac{q}{d^2} (3)

So combining (2) with (3), we find a relationship between the original field and the new field:

E' = 9 \cdot (4E) = 36E

7 0
3 years ago
What is frictional less pulley​
Talja [164]

Answer:

Conditions under which the belt and pulleys are operating – The friction between the belt and pulley may decrease substantially if the belt happens to be muddy or wet, as it may act as a lubricant between the surfaces.

Explanation:

I hope that this would be helpful

7 0
3 years ago
According to newtons first law,if no net force acts on a object,the object continues in motion with?
Dovator [93]
The object keps going cause of wind friction
6 0
4 years ago
Read 2 more answers
What is the mass of an object that has a 250 N force moving at an acceleration of 10 m/s2 ?
zzz [600]
Answer: 25 kg

Identify the given information.
f = 250 N
a = 10 m/s^2 
 
Choose which formula you should use. In this case, you are finding the mass.
The formula for force is f = ma, so, using this, it is easy to find the mass.

f = ma         Divide by a for both sides
m = f/a        Formula for mass!

The formula for mass is m = f/a, where f is force and a is acceleration.

Substitute.
m = (250 N)/(10 m/s^2)
m = 25 kg

5 0
4 years ago
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