Steve walks from his house 5 km South then turns east and walks 2 km. Then he walks 9 km North to his older sister's house. She
1 answer:
Given :
Steve walks from his house 5 km South then turns east and walks 2 km. Then he walks 9 km North to his older sister's house. She gives him a ride to his friend Fred's house 2 km West.
To Find :
The total distance covered by Steve .
Solution :
We know , distance is the actual measurement space between two points .
Now , total distance travelled by Steve is the sum of all distance travelled .
So , total distance covered by Steve is 18 km .
Hence , this is the required solution .
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accelerating
Explanation:
If we consider(v > u) Acceleration:
final velocity(v)= 14m/s
initial velocity(u)=10m/s
time taken(t)= 2 seconds
a= =2m/s²
If we consider (v<u) Deceleration:
final velocity(v)= 3m/s
initial velocity(u)=9m/s
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a = (v-v)/t ..........(i)
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t is the time taken to change velocity
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final velocity, v =11 m/s
time taken, t = 3 s
putting the values in equation (i),
a = ( 11-5 )/3
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