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nirvana33 [79]
3 years ago
5

Steve walks from his house 5 km South then turns east and walks 2 km. Then he walks 9 km North to his older sister's house. She

gives him a ride to his friend Fred's house 2 km West. Find his distance
Physics
1 answer:
rodikova [14]3 years ago
4 0

Given :

Steve walks from his house 5 km South then turns east and walks 2 km. Then he walks 9 km North to his older sister's house. She gives him a ride to his friend Fred's house 2 km West.

To Find :

The total distance covered by Steve .

Solution :

We know , distance is the actual measurement space between two points .

Now , total distance travelled by Steve is the sum of all distance travelled .

T=5+2+9+2\\\\T=18\ km

So , total distance covered by Steve is 18 km .

Hence , this is the required solution .

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A 0.70-kg disk with a rotational inertia given by MR 2/2 is free to rotate on a fixed horizontal axis suspended from the ceiling
Setler [38]

Answer:

The force will be "9.8 N".

Explanation:

The given values are:

mass,

m = 0.7 kg

M = 2

g = 9.8

Now,

⇒  \tau = T \alpha

then,

⇒  \frac{1}{2}mR^2(\frac{1}{R}\frac{dv}{dt}) =M(g-a_t)R

⇒  \frac{1}{2}m \ a_t=m(g-a_t)

⇒  a_t=\frac{2g}{(\frac{m}{M} +2)}

On substituting the values, we get

⇒      =\frac{2\times 9.8}{\frac{0.7}{2} +2}

⇒      =8.34 \ m/s

hence,

⇒  T=mg+M(g-a_t)

On substituting the values, we get

⇒      =0.7\times 9.8+2(9.8-8.34)

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⇒      =6.86+2.92

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A megawatt is larger than a kilowatt. The scientific notation for kilo is 10 to the 3, meaning 1000. A mega is 10 to the 6, meaning one million. That means a kilo watt is a thousand watts, and mega is a million watts
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To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 cm long (measured from the
lorasvet [3.4K]

Answer:

Xc = 64.27 cm, Yc = 0 cm, Xc = 27.73 cm, Yc = 18.27 cm

Explanation:

A human leg is 92 cm long equally divided into two parts (upper leg and lower leg) that is both are 46 cm long

M1 = 8.35 kg

M2 = 5.50 kg

A. Starting from hip joint, when the leg is placed horizontally, the X coordinate of centre of mass will be

Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50 x 92) / 8.35 + 5.50

( here we took x2 = 92 cm because we are measuring length from the hip joint, that means length at hip joint is 0 and at the foot 92 cm)

Xc = 890.1 / 13.85

Xc = 64.27 cm

B. Yc = (y1m1 + y2m2) / m1 + m2

Yc = (0x8.35 + 0x5.50) / 8.35 + 5.50

( here y1 and y2 are 0 because the leg is placed horizontally that means in X direction so none of the leg component is in Y direction)

Yc = 0 cm

C. Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50x0) / 8.35 + 5.50

(here x2 is taken 0 because the other half leg is bent vertically that means it is in Y direction so its X component is 0)

Xc = 384.1 / 13.85

Xc = 27.73 cm

D. Yc = (m1y1 + m2y2) / m1 + m2

Yc = (8.35x0 + 5.50x46) / 8.35 + 5.50

(here y1 is zero because the upper leg is in X direction and y2 is taken 46 cm because starting measuring from hip joint 46 cm of length of lower leg is in Y direction)

Yc = 253/13.85

Yc = 18.27 cm

7 0
3 years ago
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