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Paladinen [302]
3 years ago
5

The change in an object's volume that occurs when heat is added is called

Chemistry
2 answers:
deff fn [24]3 years ago
5 0
A. Thermal Expansion

Hope this helps :)
sergiy2304 [10]3 years ago
5 0
Thermal expansion buddy good luck i hope its helps
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What relationship does Avogadro's law describe?
LenaWriter [7]

Answer:

D. The relationship between volume and moles

Explanation:

Amedo Avogadro found the relationship between the volume of a gas and the number of molecules contained in the volume.

The law states that "equal volume of all gases at the same temperature and pressure contains the same number of molecules or moles".

Mathematically:

                         V ∝ n (P,T constant)

4 0
3 years ago
__C2H4+__O2-->__CO2+__H2O
mihalych1998 [28]

Answer:

Here is your answer mate :D

3 0
3 years ago
What path does water take as it collects salt while flowing to the ocean?
vichka [17]

Answer:Ocean water is constantly moving, and not only in the form of waves and tides. Ocean currents flow like vast rivers, sweeping along predictable paths. Some ocean currents flow at the surface; others flow deep within water. Some currents flow for short distances; others cross entire ocean basins and even circle the globe.

By moving heat from the equator toward the poles, ocean currents play an important role in controlling the climate. Ocean currents are also critically important to sea life. They carry nutrients and food to organisms that live permanently attached in one place, and carry reproductive cells and ocean life to new places.

Explanation:

i got this off my chemistry sight.. your welcome

6 0
2 years ago
If 3.31 moles of argon gas occupies a volume of 100 L what volume does 13.15 moles of argon occupy under the same temperature an
kumpel [21]

Answer:

397 L

Explanation:

Recall the ideal gas law:

\displaystyle PV = nRT

If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:

\displaystyle \frac{P}{RT} = \frac{n}{V}

The left-hand side is simply some constant. Hence, we can write that:

\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}

Substitute in known values:

\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})}  = \frac{(13.15\text{ mol })}{V_2}

Solving for <em>V</em>₂ yields:

\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}

In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.

(Assuming 100 L has three significant figures.)

3 0
2 years ago
I'm just looking for someone to check my answers on this and correct me if I'm wrong :)
Llana [10]
I believe you are right
5 0
3 years ago
Read 2 more answers
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