The answer would be C to this question!
Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.
On addition of 0.25 moles of C gas, the mole fraction of gas A will be 
.
The partial pressure of gas A can be written as 
= 
×P (where is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.
The mole fraction of gas A in a mixture of gas A and C is = 
and 
respectively.
Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be .
Which is different from the initial state.
<span>2<span>N2</span>+3<span>H2</span>→2N<span>H3
That's the balanced equation. As shown, 4 molecules of N2 would react with 12 molecules of H2. Since not that much H2 molecules exist, then it would serve as the limiting reactant. Therefore:
9 mol H2 * (2NH3 / 3H2) = 6 molecules of ammonia
</span></span>
Answer:
1.306 × 10^24 formula units.
Explanation:
The chemical equation of this qkrstios as follows:
Fe + 2H2O → FeO2 + 2H2
Based on the reaction, 2 mole of H2O produces 1 mole of FeO2
Using the formula as follows;
Mole = mass/molar mass
Molar mass of H2O = 1(2) + 16 = 18g/mol
mole = 78/18
mole = 4.33moles
If 2 mole of H2O reacts to produce 1 mole of FeO2
4.33 moles of H2O will produce 4.33/2 = 2.17moles of FeO2.
To convert moles to formula units, we multiply number of moles by Avagadro number (6.02 × 10^23 units)
= 2.17 moles × 6.02 × 10^23 units
= 13.06 × 10^23
= 1.306 × 10^24 formula units.
