Answer:
Explanation:
Given
mass of chair m=21 kg
Force required to set chair in motion is 175 N
Once the chair is in motion 137 N is require to move it with constant velocity
i.e. 175 N is the amount of force needed to just overcome static friction and 137 is the kinetic friction force
thus
where 
is the coefficient of static friction and N is Normal reaction
Answer:
if the image is on the book yes , no its can be both
Explanation:
I'm going to assume this is over a horizontal distance. You know from Newton's Laws that F=ma --> a = F/m. You also know from your equations of linear motion that v^2=v0^2+2ad. Combining these two equations gives you v^2=v0^2+2(F/m)d. We can plug in the given values to get v^2=0^2+2(20/3)0.25. Solving for v we get v=1.82 m/s!
Answer: D. Along the surface of the hill toward the top of the hill.
Hope I helped you!
