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Charra [1.4K]
1 year ago
14

Please help help help mee

Physics
1 answer:
vampirchik [111]1 year ago
4 0

Answer:

.60 A

Explanation:

The RMS (Root Mean Square) voltage (the effective voltage) of the  PEAK voltage  is  .7 * peak

.7 * 425 = 297.5 v

Now,   V = IR        re-arranged   to   V/R = I

                                                         297.5 v  /  500 ohm = .595 A = ~ .6 A

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Where,

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n_i= Lower energy level = 2

Putting the values, in above equation, we get:

\frac{1}{\lambda}=(10973731.6)\left(\frac{1}{2^2}-\frac{1}{3^2} \right )

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Now we have to calculate the energy.

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where,

h = Planck's constant = 6.626\times 10^{-34}Js

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Putting the values, in this formula, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{6.56\times 10^{-7}m}

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Therefore, the energy of one photon of hydrogen atom is, 3.03\times 10^{-19}J

3 0
3 years ago
Imagine a 15 kg block moving with a velocity of 20 m/s to the left. Calculate the kinetic Energy of this block.
ivann1987 [24]

Answer:

3000 J

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KE = 3000 J

3 0
3 years ago
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