All categories

2 years ago

Please help help help mee

Physics

1 answer:

vampirchik [111]2 years ago

4 0

Answer:

.60 A

Explanation:

The RMS (Root Mean Square) voltage (the effective voltage) of the PEAK voltage is .7 * peak

.7 * 425 = 297.5 v

Now, V = IR re-arranged to V/R = I

297.5 v / 500 ohm = .595 A = ~ .6 A

You might be interested in

If velocity is positive, which woul

shusha [124]

Answer:

C. An inital volocity that is faster than the final volocity

Explanation:

5 0

3 years ago

What is the net force on the purple ring in the picture above. _________

Dmitrij [34]

Answer:

equal

Explanation:

Because of Newton's third law

8 0

3 years ago

Which statement describes what some people might consider a benefit of wireless technology?

dangina [55]

Answer:

Uhhh

Explanation:

I dont know

8 0

3 years ago

Read 2 more answers

Hi :) I don’t really understand why it’s A

Troyanec [42]

Answer:

Explanation:

1. When the block moves across a table top, F(pulling) = - F(frictional).

Sum of this forces = 0, so the block moves with uniform speed.

2. When the block is pulled on top of the table covered with beads

F(pulling) > - F(frictional).

So, the sum of forces (∑F) is a number that is more than 0 and directed to the direction of movement.

So, a = ∑F / m is positive and constant. Speed is increasing because

v(t) = v(0)+at

a is constant and directed forward.

That means a is acceleration, and constant.

6 0

4 years ago

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d

KIM [24]

Answer:

a)Car E = Car D > (Car F = Car B = Car C) > Car A

b)Car E = Car D > (Car F = Car B = Car C) > Car A

Explanation:

Car A: mass = 500 kg; speed = 10 m/s

Car B: mass = 2000 kg;speed = 5 m/s

Car C:mass = 500 kg; speed = 20 m/s

Car D: mass = 1000 kg; speed = 20 m/s

Car E:mass = 4000 kg; speed = 5 m/s

Car F: mass = 1000 kg; speed = 10 m/s

Part a) Now we know that momentum of each car is product of mass and velocity , so we will have

$P_1 = m \times v\\P_1 = (500)(10)\\P_1 = 5 \times 10^3 kg m/s$

<em>Car B:</em>

$P_2 = m v\\P_2 = (2000)(5)\\P_2 = 10^4 kg m/s$

Car C:

$P_3 = m v\\P_3 = (500)(20)\\P_3 = 10^4 kg m/s$

Car D:

$P_4 = m v\\P_4 = (1000)(20)\\P_4 = 2\times 10^4 kg m/s$

Car E:

$P_5 = m v\\P_5 = (4000)(5)\\P_5 = 2\times 10^4 kg m/s$

Car F:

$P_6 = m v\\P_6 = (1000)(10)\\P_6 = 10^4 kg m/s$

So the momentum is given as ,

Car E = Car D > (Car F = Car B = Car C) > Car A

Part b)Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Car E = Car D > (Car F = Car B = Car C) > Car A

3 0

3 years ago