The magnitude of the force on the left-hand pole of the thin flexible gold chain of uniform linear density with a mass of 17.1 and, hangs between two 30.0 cm long vertical sticks, which are a distance of 30.0 cm apart will be, 0.167N.
To find the correct answer, we have to know more about the Basic forces that acts upon a body.
<h3>What is force and which are the basic forces that acts upon a body?</h3>
- A push or a pull which changes or tends to change the state or rest, or motion of a body is called Force.
- Force is a polar vector as it has a point of application.
- Positive force represents repulsion and the negative force represented attraction.
- There are 3 main forces acting on a body, such as, weight mg, normal reaction N, and the Tension or pulling force.
<h3>How to solve the problem?</h3>
- We have given that, the gold chain hangs between the vertical sticks of 30cm and the horizontal distance between then is 30cm.
- From the given data, we can find the angle (in the free body diagram, it is given as θ).
- From the free body diagram given, we can write the balanced equations of total force along y direction as,
- From the free body diagram given, we can write the balanced equations of total force along x direction as,
Thus, we can conclude that, the magnitude of force on the left-hand pole will be 0.167N.
Learn more about the Basic forces that acts upon a body here:
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Answer: 5m/L^2
Explanation:
Inertial I = mr^2 where r = distance from axis of rotation, while m is the mass of the object.
I = 2[m(1L/2)^2] + 2[m(3L/2)^2] = 2m×. 25/L^2+ 3m×2. 25/L^2= 0. 5m/l^2 +4. 5m/l^2
= 5m/l^2.
<span> Its A. Tue:the basic functional and structural unit of mature compact bone; run parallel to the diaphysis; has a central canal, concentric lamellae, osteocytes, canaliculi, perforating canals, circumferential lamellae, and interstitial lamellae </span>
b. seismic waves need a medium for propagation.
<h2>
Answer: 450 Bq</h2>
Explanation:
This problem can be solved using the Radioactive Half Life Formula:
(1)
Where:
is the final amount of radioisotope (decay rate)
is the initial amount of the radioisotope
is the time elapsed
is the half life of the radioisotope
Knowing this, let's find from (1):
(2)
(3)
Finally:
>>> This is the decay rate of the radioisotope
Note it is in Becquerels (Bq), which is the derived unit approved by the <u>International System of Units</u> for radioactivity