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Aleks04 [339]
3 years ago
10

A hydrate of CoCl2 with a mass of 6.00 g is heated strongly. After cooling, the mass of the anhydrate is 3.27 g.

Chemistry
1 answer:
ivann1987 [24]3 years ago
5 0
A hydrate is a substance that contains water or its constituent elements. When this substance is heated, water is evaporated leaving an unhydrate. From this sample, the amount of water present would be equal to 2.73 g. Hope this answers the question. Have a nice day.
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Balance the following redox reaction by inserting the appropriate coefficients. SO4^2- + NH3 = SO3^2- + H2O + N2
Harlamova29_29 [7]

SO₄²⁻  +NH₃  →   SO₃²⁻ + H₂O  +N₂

The  balanced  of  the above  redox reaction   is as below

3SO₄²⁻ + 2NH₃   →  3SO₃²⁻  + 3 H₂O  + N₂


 Explanation

According   to the law of mass conservation the  number  of atoms  in the reactant side  must  be equal to number of atoms in product side.

Inserting coefficient 3 in front of SO₄² , 2  in front  of NH₃, 3 in front  of SO₃²⁻  and 3 in front  of H₂O balance the equation above. This  is  because  the number  of atoms  are equal in both side.

for example there are 2 atoms of N in both side of the reaction.

6 0
3 years ago
Read 2 more answers
Calculate the grams of C6H6 needed to produce 25 g of CO2<br> Show your work
Anna007 [38]

Answer:

The given reaction is a combustion reaction of benzene,

C

6

H

6

. From its balanced chemical equation,

2

C

6

H

6

+

15

O

2

→

12

C

O

2

+

6

H

2

O

,

the mass of carbon dioxide

(

C

O

2

)

produced from 20 grams (g) of

C

6

H

6

is determined through the molar mass of the two compounds, given by,

M

M

C

O

2

=

44.01

g

/

m

o

l

M

M

C

6

H

6

=

78.11

g

/

m

o

l

and their mole ratio:

12

m

o

l

C

O

2

2

m

o

l

C

6

H

6

→

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

With this,

m

a

s

s

o

f

C

O

2

=

(

20

g

C

6

H

6

)

(

1

m

o

l

C

6

H

6

78.11

g

C

6

H

6

)

(

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

)

(

44.01

g

C

O

2

1

m

o

l

C

O

2

)

=

(

20

)

(

6

)

(

44.01

)

g

C

O

2

78.11

=

5281.2

g

C

O

2

78.11

m

a

s

s

o

f

C

O

2

=

67.6

g

C

O

2

Therefore, the mass in grams of

C

O

2

formed from 20 grams of

C

6

H

6

is

67.6

g

C

O

2

.

it is a problem of app

3 0
2 years ago
Which organism would have the most variation in the DNA of its offspring?
Arada [10]

The organism that would have the most variation in the DNA of its offspring is the cat (Option C). Meiosis is a type of cell division that generates more genetic variability than asexual types of reproduction.

Meiosis is a type of reductional cell division by which a parental cell produces 4 daughter cells (gametes), each containing half of the genetic material.

Animals (e.g., cats) generate gametes by meiosis which fuse during fertilization to produce new offspring.

Both amoeba and bacteria reproduce by a type of asexual reproduction called binary fission. Moreover, yeasts also reproduce asexually by a process called budding and fission.

Both asexual and sexual types of reproduction generate genetic variability by the emergence of new mutations in daughter cells.

Meiosis generates much more genetic variability than asexual types of reproduction due to two different processes:

  • Random assortment of chromosomes, which produces new allele combinations.

  • Recombination, i.e., by the exchange of genetic material (DNA) between non-sister chromatids during Prophase I.

Learn more in:

brainly.com/question/7002092

5 0
2 years ago
________ are chemical messengers that are released by cells and transported in the bloodstream to alter the activities of specif
Reika [66]
You may be looking for neurotransmitters
3 0
3 years ago
Using the ideal gas law, PV=nRT, where R=0.0821 L atm/mol K, calculate the volume in liters of oxygen produced by the catalytic
AfilCa [17]

Answer:

V = 2.32 Liters

Explanation:

PV = nRT => V = nRT/P

n = 25.8g/122g/mole = 0.21 mole

R = 0.08206 L·atm/mol·K

T = 25.44°C + 273 = 298.44K

P = 2.22 atm (given in problem)

V = (0.21mol)(0.08206 L·atm/mol·K)(298.44K)/(2.22atm) = 2.32 Liters at 25.44°C & 2.22atm

8 0
3 years ago
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