A hydrate of CoCl2 with a mass of 6.00 g is heated strongly. After cooling, the mass of the anhydrate is 3.27 g.
1 answer:
You might be interested in
The relative volumes of chloroform and water that should be used is 9:10
Concentration of solution in chloroform = ( moles of chloroform )
Concentration of solution in water = ( moles of water )
Dissociation constant at ;
Concentration of solution in chloroform / Concentration of solution in water
Meaning;
Since mole is present in chloroform and
mole is present in water, Total mole of Caffeine present is
Now, we substitute our given values into the equation
Therefore, the relative volumes of chloroform and water that should be used is 9:10
Learn more; brainly.com/question/11060225
Answer:
Reagent A: PBr₃
Reagent B: Mg in Et₂O.
Explanation:
Hello,
In this case, your facing a problem in which a carboxylic acid is produced starting by an alcohol. More specifically, cyclopentanol must react with phosphorous tribromide in order to yield bromocyclopentane which is more likely to produce a carboxylic acid, therefore, reagent A is PBr₃.
On the other hand, by means of the production of the specified product, bromocyclopentane must react with carbon dioxide and magnesium in diethyl ether in acidic media to promote the production of the cyclopentanoic acid via the grignard reaction (substitution of the bromine by the carboxyle group), therefore, reagent B is Mg in Et₂O.
Best regards.
