Answer:
The molecular weight of the unknown gas is 16.1 g/mol.
The empirical formula for a compound is KClO3
Explanation
find the moles of each element
moles = % composition/molar mass
molar mass of of potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol
moles of potassium = 31.9 / 39 = 0.818 moles
moles of chlorine = 28.9/35.5 = 0.814 moles
moles of oxygen = 39.2/ 16 = 2.45 moles
find the mole ratio by dividing with the smallest mole = 0.814 moles
potassium = 0.818/0.814 =1
chlorine = 0.814/0.814 = 1
oxygen = 2.45 /0.814 =3
the empirical formula is therefore = KClO3
B and D is out. It cant be A because heat of combustion is substance not compound. So the answer is D.
Answer:
Oxygen is in group 16/VIA, which is called the chalcogens, and members of the same group have similar properties. Sulfur and selenium are the next two elements in the group, and they react with hydrogen gas (H2) in a manner similar to oxygen.
Explanation:
The balanced thermochemical equation is
KBr ------- K + 1/2 Br2
<h3>What is thermochemical equation? </h3>
A Thermochemical Equation is defined as the balanced stoichiometric chemical equation which includes the enthalpy change, ΔH.
The chemical equation for the decomposition of potassium bromide to its constituent elements bromine ans potassium :
KBr ----- K + Br2
The balanced thermochemical equation of the decomposition of potassium bromide to its constituent elements potassium and bromide as follows
KBr ------- K + 1/2 Br2
As the heat is absorbed in this reaction therefore, heat is positive.
Thus, we concluded that the balanced thermochemical equation is
KBr ------- K + 1/2 Br2
learn more about thermochemical equation:
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