Answer:
Their common velocity after collision is 3.6 m/s
Explanation:
Given;
mass of the first meatball, m₁ = 3.0 kg
initial velocity of the first meatball, u₁ = 6.0 m/s
mass of the second meatball, m₂ = 2.0 kg
initial velocity of the first meatball, u₂ = 0 m/s
let their common velocity after collision = v
Apply the principle of conservation of linear momentum for inelastic collision ;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(3 x 6) + (2 x 0) = v( 3 + 2)
18 = 5v
v = 18 / 5
v = 3.6 m/s
Therefore, their common velocity after collision is 3.6 m/s
Answer:
I think no B
if wrong correct me plsssssss
Mark me brainliest
have a nice day
I will always help you understanding your assingments
#Captainpower:)
Answer:
μ = 0.104
Explanation:
Given that
m = 1114 kg
s= 6.7 km = 670 m
Initial velocity ,u = 425 km/h
1 km/h= 0.27 m/s
u= 118.056 m/s
The final velocity of car ,v= 0 m/s
We know that
v² = u² + 2 a s
a=Acceleration
Now by putting the values
0² = 118.056² + 2 x a x 670
a=-\dfrac{118.056^2}{2\times 670} m/s^2
a= - 10.4 m/s²
The acceleration also given as
a = - μ g ( fr = m μ g = - m a)
10.4 = 10 x μ ( take g= 10 m/s²)
μ = 0.104
Therefore the coefficient of kinetic friction will be 0.104 .
Answer:
15.88°C I am not 100% sure this is right but I am 98% sure this IS right