Question

A spring is compressed so that it has 7.2 J of elastic potential energy. A 0.3 kg ball is placed on top of the spring. When the spring is released, how high will the ball go ?

Answer 1

The height of the ball is 2.45 m.

To calculate the height of the ball, we use the formula below.

Formula

• E = mgh................ Equation 1

Where:

• E = Elastic energy of the spring
• m = mass of the ball
• h = height of the ball
• g = acceleration due to gravity.

make h the subject of the equation

• h = E/mg...............Equation 2

From the question,

Given:

• E = 7.2 J
• m = 0.3 kg
• g = 9.8 m/s²

Substitute these  values into equation 2

• h = 7.2/(0.3×9.8)
• h = 7.2/2.94
• h = 2.45 m

Hence, The height of the ball is 2.45 m.

Learn more about height here: brainly.com/question/1739912