A spring is compressed so that it has 7.2 J of elastic potential energy. A 0.3 kg ball is placed on top of the spring. When the
spring is released, how high will the ball go ?
1 answer:
The height of the ball is 2.45 m.
To calculate the height of the ball, we use the formula below.
<h3>Formula</h3>
- E = mgh................ Equation 1
Where:
- E = Elastic energy of the spring
- m = mass of the ball
- h = height of the ball
- g = acceleration due to gravity.
make h the subject of the equation
- h = E/mg...............Equation 2
From the question,
Given:
- E = 7.2 J
- m = 0.3 kg
- g = 9.8 m/s²
Substitute these values into equation 2
- h = 7.2/(0.3×9.8)
- h = 7.2/2.94
- h = 2.45 m
Hence, The height of the ball is 2.45 m.
Learn more about height here: brainly.com/question/1739912
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