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MariettaO [177]
2 years ago
9

A spring is compressed so that it has 7.2 J of elastic potential energy. A 0.3 kg ball is placed on top of the spring. When the

spring is released, how high will the ball go ?
Physics
1 answer:
VLD [36.1K]2 years ago
5 0

The height of the ball is 2.45 m.

To calculate the height of the ball, we use the formula below.

<h3>Formula</h3>
  • E = mgh................ Equation 1

Where:

  • E = Elastic energy of the spring
  • m = mass of the ball
  • h = height of the ball
  • g = acceleration due to gravity.

make h the subject of the equation

  • h = E/mg...............Equation 2

From the question,

Given:

  • E = 7.2 J
  • m = 0.3 kg
  • g = 9.8 m/s²

Substitute these  values into equation 2

  • h = 7.2/(0.3×9.8)
  • h = 7.2/2.94
  • h = 2.45 m

Hence, The height of the ball is 2.45 m.

Learn more about height here: brainly.com/question/1739912


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Answer:

1. 0.45 s.

2. 4.41 m/s

Explanation:

From the question given above, the following data were obtained:

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1. Determination of the time taken for the pencil to hit the floor.

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Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

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t = 0.45 s.

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2. Determination of the velocity with which the pencil hit the floor.

Initial velocity (u) = 0 m/s

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Time (t) = 0.45 s.

Final velocity (v) =?

v = u + gt

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Answer:

the <em>ratio F1/F2 = 1/2</em>

the <em>ratio a1/a2 = 1</em>

Explanation:

The force that both satellites experience is:

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