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MariettaO [177]

2 years ago

9

A spring is compressed so that it has 7.2 J of elastic potential energy. A 0.3 kg ball is placed on top of the spring. When the

spring is released, how high will the ball go ?

1 answer:

VLD [36.1K]2 years ago

5 0

The height of the ball is 2.45 m.

To calculate the height of the ball, we use the formula below.

<h3>Formula</h3>

E = mgh................ Equation 1

Where:

E = Elastic energy of the spring
m = mass of the ball
h = height of the ball
g = acceleration due to gravity.

make h the subject of the equation

h = E/mg...............Equation 2

From the question,

Given:

E = 7.2 J
m = 0.3 kg
g = 9.8 m/s²

Substitute these values into equation 2

h = 7.2/(0.3×9.8)
h = 7.2/2.94
h = 2.45 m

Hence, The height of the ball is 2.45 m.

Learn more about height here: brainly.com/question/1739912

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