Answer:
1)
2) x = 0.28 m from cable A.
Explanation:
1 ) Let's use the first Newton to find the , because bar is in equilibrium.
In this case we just have y-direction forces.
Now, let's solve the equation for W(object).
2 ) To find the position of the heaviest weight we need to use the torque definition.
The total torque is evaluated in the axes of the object.
Let's put the heaviest weight in a x distance from the cable A. We will call this point P for instance.
First let's find the positions from each force to the P point.
; total length of the bar.
; distance between Tension A and P point.
; distance between Tension B and P point.
; distance between weight of the bar (middle of the bar) and P point.
Now, let's find the total torque in P point, assuming counterclockwise rotation as positive.
Finally we just need to solve it for x.
So the distance is x = 0.28 m from cable A.
Hope it helps!
Have a nice day! :)