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3 years ago

Sometimes it is very hard to hear in a gymnasium because of echoes . How can you changed it

1 answer:

7 0

A couple ways to reduce the bouncing of sound waves are to put foam in the wall and put slits down the wall so the sound is asorbed, another way is to hang soft mats of foam from the ceiling, that also asorbs the rogue sound waves.

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If the period of oscillation of a simple pendulum is 4s, find its length. If the velocity of the bob

Natalija [7]

Answer:

Explanation:

Because we assume the pendulum is a "mathematical pendulum" (neglecting the moment of inertia of the bob), we can find:

$T=2\pi\sqrt{\frac{L}{g}} \rightarrow 4=2\pi\sqrt{\frac{L}{9.81}} \rightarrow \frac{4}{\pi^{2}}=\frac{L}{9.81} \rightarrow L \approx 3.97 m$

By using the $y=A\sin(\omega t) \rightarrow v = \frac{dy}{dt}=\omega A \cos\omega t = \omega\sqrt{A^{2}-y^{2}}$

The mean position is the position when y = 0, so:

$\omega = \frac{2\pi}{T}=\frac{2\pi}{4}=0.5\pi$ rad/s

and $v = \omega A \rightarrow A=\frac{40}{0.5\pi}=\frac{80}{\pi}$ in centimeters (cm).

4 0

2 years ago

Which of the following statements is true regarding the constructive interference diagram shown below? Select all that apply.

yulyashka [42]

Answer:

I believe its B and C

Explanation:

If I'm wrong please tell me so I can correct my answer.

6 0

2 years ago

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Calculate the energy needed to heat 4 kg of water from 25°C to 45°C.

inna [77]

(1 cal/g °C) x (4000 g) x (45 - 25)°C = 80000 cal = 80 kcal. So the answer is 80 kcal .

8 0

3 years ago

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A 5.45-g combustible sample is burned in a calorimeter. the heat generated changes the temperature of 555 g of water from 20.5°c

Y_Kistochka [10]

Given:
m = 555 g, the mass of water in the calorimeter
ΔT = 39.5 - 20.5 = 19 °C, temperature change
c = 4.18 J/(°C-g), specific heat of water

Assume that all generated heat goes into heating the water.
Then the energy released is
Q = mcΔT
= (555 g)*(4.18 J/(°C-g)*(19 °C)
= 44,078.1 J
= 44,100 J (approximately)

Answer: 44,100 J

3 0

2 years ago

Below is the data from a gas law experiment comparing the pressure and the volume of a gas at a given temperature.

Wewaii [24]

Answer:

The combined gas equation relates three variables pressure, temperature and volume when the number of moles is constant.

The equation is PV / T = constant. Which is valid for a fixed number of moles of the gas.

You can derive the combined gas equation from the combination of Bolye's law, Charles' law and Gay-Lussac's law, which needs some algebra.

Explanation:

9 0

2 years ago

Read 2 more answers