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den301095 [7]
3 years ago
10

Sometimes it is very hard to hear in a gymnasium because of echoes . How can you changed it

Physics
1 answer:
BlackZzzverrR [31]3 years ago
7 0
A couple ways to reduce the bouncing of sound waves are to put foam in the wall and put slits down the wall so the sound is asorbed, another way is to hang soft mats of foam from the ceiling, that also asorbs the rogue sound waves.
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ILL GIVE BRAILIST THING
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<h2>8 mL</h2>

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The volume of the chess can be found by using the formula

volume = final volume of water - initial volume of water

From the question

final volume of water = 43 mL

initial volume of water = 35 mL

We have

volume = 43ml - 35ml = 8 mL

We have the final answer as

<h3>8 mL</h3>

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The increasing speed of a falling object is caused by
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gravity

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In a physics laboratory experiment, a coil with 200 turns enclosing an area of 13.1 cm2 is rotated during the time interval 3.10
sergij07 [2.7K]

Answer:

A)\Phi=83.84\times 10^{-9}

B)\Phi=0 Wb

C)emf=5.4090\times 10^{-4}V

Explanation:

Given that:

  • no. of turns i the coil, n=200
  • area of the coil, a=13.1 \times 10^{-4}\,m^2
  • time interval of rotation, t=3.1\times 10^{-2}\,s
  • intensity of magnetic field, B=6.4\times 10^{-5}\,T

(A)

Initially the coil area is perpendicular to the magnetic field.

So, magnetic flux is given as:

\Phi=B.a\,cos \theta..................................(1)

\theta is the angle between the area vector and the magnetic field lines. Area vector is always perpendicular to the area given. In this case area vector is parallel to the magnetic field.

\Phi=6.4\times 10^{-5}\times 13.1 \times 10^{-4}\, cos 0^{\circ}

\Phi=83.84\times 10^{-9} Wb

(B)

In this case the plane area is parallel to the magnetic field i.e. the area vector is perpendicular to the magnetic field.

∴  \theta=90^{\circ}

From eq. (1)

\Phi=6.4\times 10^{-5}\times 13.1 \times 10^{-4}\, cos 90^{\circ}

\Phi=0 Wb

(C)

According to the Faraday's Law we have:

emf=n\frac{B.a}{t}

emf=\frac{200\times 6.4\times 10^{-5}\times 13.1 \times 10^{-4}}{3.1\times 10^{-2}}

emf=5.4090\times 10^{-4}V

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3 years ago
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