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pogonyaev
3 years ago
10

Write the symbol for element x which has 22 electrons and 22 neutrons

Chemistry
1 answer:
marissa [1.9K]3 years ago
7 0
Titanium has 22 protons and electrons. The symbol for Titanium is (Ti).
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4 cups are about 0.25 gallons

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To convert a cup measurement to a gallon measurement, divide the volume by the conversion ratio. The volume in gallons is equal to the cups divided by 16.

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A solution that is able to dissolve additional solute is best described as
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<h2>Question:</h2>

  • A solution that is able to dissolve additional solute is best described as _____.

<h2>Answer:</h2>

<h2>D.) Unsaturated </h2>

  • <u>Unsaturated</u> means the substance is poured into the solvent that can be dissolved. It is a solution (with less solute than the saturated solution) that completely dissolves, leaving with no remaining substances.

<h2>For example:</h2>

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4 0
2 years ago
Calculate Ho298 for the process
Inga [223]

Explanation:

As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Sb + \frac{3}{2}Cl_2 \rightarrow SbCl_{3}    \Delta H^0_1 =  -314 kJ  ..........(1)

SbCl_{3} + Cl_2 \rightarrow SbCl_{5}    \Delta H^0_2 = -80kJ   ..............(2)

The final reaction is as follows:  

Sb + \frac{5}{2}Cl_{2} \rightarrow SbCl_{5}  \Delta H^0_3 = ?  .............(3)

Therefore, adding (1) and (2) we get the final equation (3) and value of \Delta H^{0}_{3} at 298 K will be as follows.

             \Delta H^{0}_{3} = \Delta H^{0}_{1} + \Delta H^{0}_{2}    

                       = -314 kJ + (-80) kJ

                       = -394 kJ

Thus, we can conclude that H^{o} at 298 K for the given process is -394 kJ.

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The answer is C.

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