Answer: option 1 : the electric potential will decrease with an increase in y
Explanation: The electric potential (V) is related to distance (in this case y) by the formulae below
V = kq/y
Where k = 1/4πε0
Where V = electric potential,
k = electric constant = 9×10^9,
y = distance of potential relative to a reference point, ε0 = permittivity of free space
q = magnitude of electronic charge = 1.609×10^-19 c
From the formulae, we can see that q and k are constants, only potential (V) and distance (y) are variables.
We have that
V = k/y
We see the potential(V) is inversely proportional to distance (y).
This implies that an increase in distance results to a decreasing potential and a decrease in distance results to an increase in potential.
This fact makes option 1 the correct answer
It will help them stay in better shape resulting in better health, being more physically active, and staying happier as a result.
Answer:
An <u>applied force</u> is a force that is applied to an object by a person or another object. If a person is pushing a desk across the room, then there is an applied force acting upon the object. The applied force is the force exerted on the desk by the person.
A <u>friction force</u> is the force exerted by a surface as an object moves across it or makes an effort to move across it. There are at least two types of friction force - sliding and static friction. Though it is not always the case, the friction force often opposes the motion of an object. For example, if a book slides across the surface of a desk, then the desk exerts a friction force in the opposite direction of its motion. Friction results from the two surfaces being pressed together closely, causing intermolecular attractive forces between molecules of different surfaces. As such, friction depends upon the nature of the two surfaces and upon the degree to which they are pressed together. The maximum amount of friction force that a surface can exert upon an object can be calculated using the formula below:
= µ •
Answer: 22.6 hours
Explanation:
The power is the measure of the rate of energy.
In this problem, the 12.0 V battery is rated at 51.0 Ah, which means it delivers 51.0 A of current in a time of t = 1 h = 3600 s. The power delivered by the battery can be written as
![P=IV](https://tex.z-dn.net/?f=P%3DIV)
where
I is the current
V = 12.0 V is the voltage of the battery
So the energy delivered by the battery can be written as
![E=Pt=VIt](https://tex.z-dn.net/?f=E%3DPt%3DVIt)
Where
![It=51.0 A\cdot h = 51.0 A \cdot 3600 s/h=183,600 A\cdot s](https://tex.z-dn.net/?f=It%3D51.0%20A%5Ccdot%20h%20%3D%2051.0%20A%20%5Ccdot%203600%20s%2Fh%3D183%2C600%20A%5Ccdot%20s)
So the energy delivered is
![E=(12.0)(183,600)=2.2\cdot 10^6 J](https://tex.z-dn.net/?f=E%3D%2812.0%29%28183%2C600%29%3D2.2%5Ccdot%2010%5E6%20J)
At the same time, the headlight consumes 27.0 W of power, so 27 Joules of energy per second; Therefore, it will remain on for a time of:
![t=\frac{2.2\cdot 10^6 J}{27.0 W}=81481 s = 22.6 h](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.2%5Ccdot%2010%5E6%20J%7D%7B27.0%20W%7D%3D81481%20s%20%3D%2022.6%20h)
Elliptical and Spiral have some similarities, they both are huge and contain lost of dust and also they are held by gravitational forces.