I do believe that the answer is D.
Hope this is right! Have a great day! :-)
Answer:
Velocity = 0.309 m/s
Along negative x axis
Explanation:
A pulse moving to the right along the x axis is represented by the wave function
y(x,t) = 2/ (x - 3t)² + 1
At t =0
y(x,0) = 2/ ((x - 3(0))² + 1)
=2 / (x² + 1)
At t = 1
y(x,t) = 2/ ((x - 3(1))² + 1)
= 2 /(( x - 3)² + 1)
At t = 2
y(x,t) = 2/ ((x - 3(2))² + 1)
= 2 /(( x - 6)² + 1)
For the pulse with expression y(x,t) = 4.5
²
The Velocity is
V = 2.7 / 8.73
= 0.309 m/s
The work that Sam should do in order to stop is the boat is the same as that of the kinetic energy of the object in order to counter its motion. Kinetic energy is calculated through the equation,
KE = 0.5mv²
where KE is kinetic energy, m is mass, and v is the velocity.
Substituting,
KE = 0.5(1200kg)(1.2 m/s)²
<em>KE = 864 J</em>
Recall that

It takes the car about 3.2 s to reduce its speed from 14.6 to 10.8 m/s, since

Next, recall that

Then the car undergoes a displacement of about 41 m, since
