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xz_007 [3.2K]
3 years ago
7

A cat falls from a table of height 1.3m. What is the impact speed of the cat

Physics
1 answer:
Lorico [155]3 years ago
6 0

Answer: 12.753

Explanation: Multiply 1.3 and 9.81 (the speed that everything drops at.)

Also, i feel bad for the cat

it might be wrong sorry

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Marissaâs car accelerates uniformly at a rate of +2.60 m/s². How long does it take for Marissaâs car to accelerate from a speed
DIA [1.3K]

Answer:

The time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s is 0.84 seconds.

Explanation:

Given that,

Acceleration of the car, a=+2.6\ m/s^2

Initial speed of the car, u = 24.6 m/s

Final speed of the car, v = 26.8 m/s

We need to find the time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s. The acceleration of an object is given by :

t=\dfrac{v-u}{a}

t=\dfrac{(26.8-24.6)\ m/s}{2.6\ s}

t = 0.84 seconds

So, the time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s is 0.84 seconds. Hence, this is the required solution.                                    

4 0
3 years ago
2. What does the term reflection mean?
Vesna [10]

Answer:

egrfeirugherhgourehgabgwehgoehborghrewuhgelkg

Explanation:

4 0
3 years ago
A complete series circuit consists of a 12.0 V battery, a 4.70 O resistor, and a switch. The internal resistance of the battery
RoseWind [281]

With the switch open, there's no current in the circuit, and therefore
no voltage drop across any of the dissipative elements (the resistor
or the battery's internal impedance).  So the entire battery voltage
appears across the switch, and the voltmeter reads 12.0V .

4 0
3 years ago
Read 2 more answers
If you want to know how energy will move between two objects, what do you need to know about the objects?
Inessa [10]
You need to know how much friction that object.
8 0
3 years ago
A Carnot engine's operating temperatures are 240 ∘C and 20 ∘C. The engine's power output is 910 W . Part A Calculate the rate of
scoray [572]

Answer:1200

Explanation:

Given data

Upper Temprature\left ( T_H\right )=240^{\circ}\approx 513

Lower Temprature \left ( T_L\right )=20^{\circ}\approx 293

Engine power ouput\left ( W\right )=910 W

Efficiency of carnot cycle is given by

\eta =1-\frac{T_L}{T_H}

\eta =\frac{W_s}{Q_s}

1-\frac{293}{513}=\frac{910}{Q_s}

Q_s=2121.954 W

Q_r=1211.954 W

rounding off to two significant figures

Q_r=1200 W

5 0
3 years ago
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