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3 years ago

A cat falls from a table of height 1.3m. What is the impact speed of the cat

Physics

1 answer:

Lorico [155]3 years ago

6 0

Answer: 12.753

Explanation: Multiply 1.3 and 9.81 (the speed that everything drops at.)

Also, i feel bad for the cat

it might be wrong sorry

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3 years ago

English or metric <br> What is 16in to cm

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40.64 cm is the answer to your question.

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3 years ago

During a marathon race, a runner’s blood flow increases to 10.0 times her resting rate. Her blood’s viscosity has dropped to 95.

Phoenix [80]

To solve the problem it is necessary to apply the equations related to the Poiseuilles laminar flow law, with which the stationary laminar flow ΦV of an incompressible and uniformly viscous liquid (also called Newtonian fluid) can be determined through a cylindrical tube of constant circular section. Mathematically this can be expressed:

$Q = \frac{\Delta P \pi r^4}{8\eta l}$

Where:

$\eta_i =$ are the viscosities of the concrete before and after the increase

l = Length of the vessel

$r_1, R_2$ = Radio of the vessel before and after the increase

$\Delta P$ = Change in the pressure

$Q_{1,2} =$ The rates of flow before and after he increase

Our values are given as:

$Q_2 = 10Q_1 \rightarrow$ 10 times her resting rate

$\eta_2 = 0.95\eta_1$ 95% of its normal value

$\Delta P_2 = 1.5\Delta P_1$ Increase of 50%

Plugging known information to get

$Q_1 = \frac{\Delta P \pi r^4}{8\eta l}$

$Q_1 8\eta_1 l = \Delta P_1 \pi r_1^4$

$r_1^4 = \frac{Q_1 8\eta_1 l}{\Delta P_1 \pi}$

$r_1 = (\frac{Q_1 8\eta_1 l}{\Delta P_1 \pi})^{1/4}$

$r_2 = (\frac{Q_2 8\eta_2 l}{\Delta P_2 \pi})^{1/4}$

$r_2 = (\frac{10Q_18 \times 0.95\eta_1 l}{1.5\Delta P_1 \pi})^{1/4}$

$r_2 = 1.586r_1$

Therefore the factor of average radio of her blood vessels increased is 1.589 the initial factor after the increase.

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4 years ago

Bob has a brother, jim, who has a daughter named bertha. Bertha's daughter, jennifer, has a sister named penny. which of the fol

sammy [17]

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3 years ago

Read 2 more answers

In rules for naming a compound you change the negative name to end in" ide" *

Strike441 [17]

Answer:

Single-atom negative ions end in “-ide”, so binary compounds always have this ending. Polyatomic compounds usually end in “-ate” or “-ite”. FORMULAS: Write the positive ion, with its charge, then the negative ion, with its charge.

Explanation:

hope it helps, please mark as brainliest

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