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3 years ago

What mass of excess reactant remains at the end of the reaction if 90.0 g of so2 are mixed with 100.0 g of o2? 2so2 + o2 → 2so3?

1 answer:

8 0

For the reaction 2SO2 + O2 -> 2 SO3, we first determine which is the excess reactant between SO2 and O2. We list down the molar mass of the reactants:

Molar mass of SO2 = 64.0638 g/mol

Molar mass of O2 = 32 g/mol

Using the stoichiometry of the reaction, we then calculate the amount of oxygen that will react with 90.0 g of SO2.

90.0 g SO2 x 1 mol SO2/64.0638 g x 1 mol O2/ 2 mol SO2 x 32 g O2/mol = 22.4776 g O2

Thus, we can conclude that O2 is the excess reactant while SO2 is the limiting reactant. Subtracting 22.4776 g O2 from the initial 100.0 g O2, we get 77.5224 g O2 left after the complete reaction of 90.0 g SO2.

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Marjorie is trying to determine the identity of an unknown substance. After running tests, she determines that the substance is

finlep [7]

Answer:
The substance is most likely NaCl.

Explanation:
Solubility:
As stated in statement the substance is insoluble in CCl₄ (Tetrachloromethane), it shows that the substance is polar in nature. In given options only C₁₀H₈ is soluble in CCl₄ because both are non polar in nature and like dissolves like. Hence, C₁₀H₈ is rejected.

Density:
Now, we are left with three options. NaCl, FeCl₃ and SiO₂. The student found that the density of substance is 2.20 g.mL⁻¹. Which is very close to the density of NaCl (i.e. 2.165 g.mL⁻¹). Therefore, most probably the substance the student is dealing with is Sodium Chloride.

3 0

3 years ago

Read 2 more answers

Commercial concentrated aqueous ammonia is 28% NH3 by mass and has a density of 0.90 g/mL. You may want to reference (Pages 539

katen-ka-za [31]

Answer:

The molarity of this solution is 14.82 mol/dm3 or 14.82 mol/L

Explanation:

Molarity is the number of mole present in 1 Litre of solution. Molarity of a solution is a term referred to as concentration of a solution. The unit of Molarity is Mol/dm3 or Mol/L.
let us make an assumption that the volume of the ammonia solution is 1L or 1dm3. Also, 1L = 1000 mL.

Step 1: calculate the mass of the solution

Density = 0.90g/ml (from the question)

Density = mass/ volume

Therefore Mass = density x volume

= 0.90g/ml x 1000ml

mass = 900 g

Step 2: calculate the mass of NH3 present in the solution

Since the concentrated aqueous of ammonia is 28%, It signifies that 1000ml of the solution contains 28% Ammonia

Recall from the above calculation that the mass of 1000 ml of solution is 900 g.

Therefore the mass of ammonia will be 28% of 900 g

mass of NH3 = 0.28 x 900 g

= 252 g

Step 3: calculate the number of mole of NH3

mole = mass/ molar mass

molar mass of NH3 = 17 g/mol

Therefore mole of NH3 = 252/17

= 14.82 mol

Step 4: Calculate Molarity

Molarity = number of moles/ volume of solution in Litre (L)

Molarity = 14.82 / 1

Molarity = 14.82 mol/L

4 0

4 years ago

How many atoms are in water is it 24 or 2. Explain

Artemon [7]

There are actually three: One oxygen atom and two hydrogen atoms.

8 0

3 years ago

What is the chemical formula for the compound formed between sodium and selenium?

likoan [24]

Sodium is in group 1 and so will form Na+. Selenium is in group XVI (6) and so will form Se2- . Thus, the compound formed, sodium selenide, will be Na2Se

4 0

3 years ago

2.93 mol of MgF2 to grams

mojhsa [17]

The mass of 1.72 mol of magnesium fluoride is 107 grams.

To determine the mass of 1.72 mol of magnesium fluoride, we first need the chemical formula of magnesium fluoride. Magnesium forms a +2 ion (Mg+2) and fluoride forms a -1 ion (F-1). Since all compounds formed from ions have to be electrically neutral, we need 2 fluoride ions and 1 magnesium ion. Therefore, the formula for magnesium fluoride is MgF2.

Now we need to determine the molar mass of the compound from the molar mass values from the periodic table. Let's use a table to calculate this molar mass.

Molar mass of MgF2

Element Molar Mass (g/mol) Quantity Total (g/mol)

Mg 24.31 1 24.31

F 19.00 2 38.00

Total molar mass of MgF2 = 24.31 g/mol + 38.00 g/mol = 62.31 g/mol

This is the mass of one mole of the substance. If we have 1.72 mols of it, we multiply 1.72 by 62.31.

1.72 mol (62.31 g/mol) = 107 grams

We rounded to 107 to keep the correct number of significant digits in our answer.

8 0

3 years ago