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3 years ago

A chemist studies two forms of gasoline. Which of the following branches of chemistry might the chemist use?

Chemistry

2 answers:

maxonik [38]3 years ago

7 0

Answer:

Organic Chemistry

Explanation:

I can confirm that this is correct. I won't give a detailed explanation. Read your textbook or ask a teacher for help. But quickly...

Organic Chemistry: <em>subdiscipline of chemistry dedicated to the study of compounds that contain carbon.</em>

Gasoline <u>does</u> contain carbon.

yuradex [85]3 years ago

4 0

Yes its a tricky one.
Personally I would go for A.

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Which property of waves is the distance between one point on a wave and that same point on the wave next to it?

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The answer is B, wavelength

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3 years ago

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The dissolution of ammonium nitrate occurs spontaneously in water at 25°C. As NH4NO, dissolves, the temperature of the water dec

MA_775_DIABLO [31]

Answer:

ΔG <0 , ΔH > 0 , ΔS > 0 .

Explanation:

From the data given in question , the reaction is a spontaneous process , hence , the value of change in gibbs free energy would be negative , ΔG <0

And , on dissolution process , the temperature of the water decreases , i.e. , it is an endothermic process , i.e. , the change in enthalphy value is positive , ΔH > 0

And , during the process of dissolution , the ammonia salt break does to ions , i.e. , the randomness increases , hence the ΔS > 0

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3 years ago

Cual es la masa atomica promedio

kkurt [141]

Answer:

Explanation:

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3 years ago

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1. A 10 g gold coin is heated from 25°C to 50°C (CAu is 0.13 J/g-°C). What is the H?

Oksanka [162]

The correct answer is + 32.5 J because heat is absorbed here by copper not evolved also after calculation we will find the H value is positive, lets calculate it:
H = m C Δt where:
m = 10 g
C = 0.13 J/g.°C
Δ t = final temperature - initial temperature = 50 - 25 = + 25 °C
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3 years ago

Which of the following gives the molarity of a 17.0% by mass solution of sodium acetate, CH 3COONa (molar mass = 82.0 g/mol) in

weeeeeb [17]

Answer:

The molarity of this solution is 2.26 M (option D)

Explanation:

Step 1: Data given

Mass % = 17%

Molar mass of CH3COONa = 82.0 g/mol

Density of the solution = 1.09 g/mL

Step 2:

Assume the mass of the solution is 1.00 gram

⇒ 17.0 % CH3COONa = 0.17 grams

⇒ 83.0 % H2O = 0.83 grams

Step 3:

Density = 1.09 g/mL

Volume of the solution = total mass / density of solution

Volume of solution : 1.00 grams / 1.09 g/mL

Volume of the solution = 0.917 mL = 0.000917 L

Step 4: Calculate number of moles of CH3COONa

Number of moles = Mass / molar mass

Number of moles CH3COONa = 0.170 grams / 82.0 g/mol

Number of moles = CH3COONa = 0.00207 moles

Step 5: Calculate molarity

Molarity = moles / volume

Molarity solution = 0.00207 / 0.000917 L

Molarity solution = 2.26 mol/L = 2.26 M

The molarity of this solution is 2.26 M (option D)

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3 years ago