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mestny [16]
3 years ago
14

A chemist studies two forms of gasoline. Which of the following branches of chemistry might the chemist use?

Chemistry
2 answers:
maxonik [38]3 years ago
7 0

Answer:

Organic Chemistry

Explanation:

I can confirm that this is correct. I won't give a detailed explanation. Read your textbook or ask a teacher for help. But quickly...

Organic Chemistry: <em>subdiscipline of chemistry dedicated to the study of compounds that contain carbon.</em>  

Gasoline <u>does</u> contain carbon.

yuradex [85]3 years ago
4 0
Yes its a tricky one. 
Personally I would go for A.
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3 years ago
Consider 0.01 m aqueous solutions of each of the following. a) NaI; b) CaCl2; c) K3PO4; and d) C6H12O6 (glucose) Arrange the sol
stealth61 [152]

Answer:

The solutions are ordered by this way (from lowest to highest freezing point):  K₃PO₄ < CaCl₂ < NaI < glucose

Option d, b, a and c

Explanation:

Colligative property: Freezing point depression

The formula is: ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

We need to determine the i, which is the numbers of ions dissolved. It is also called the Van't Hoff factor.

Option d, which is glucose is non electrolyte so the i = 1

a. NaI →  Na⁺  +  I⁻        i =2

b. CaCl₂ →  Ca²⁺  +  2Cl⁻      i =3

c. K₃PO₄ → 3K⁺ + PO₄⁻³     i=4

Potassium phosphate will have the lowest freezing point, then we have the calcium chloride, the sodium iodide and at the end, glucose.

7 0
3 years ago
2MG+O2 ...........2MGO
Galina-37 [17]
Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced
5 0
3 years ago
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