This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:
Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻ ⇒2K⁺O⁻²H⁺ + I₂⁰
Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻
Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.
In such a way, the correct choice is C.
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Hi! :)
Ba(OH)2 + 2 HNO3 → Ba(NO3)2 + 2 H2O
(18.2 mL) x (0.45 M Ba(OH)2) x (2 mol HNO3 / 1 mol Ba(OH)2) / (38.5 mL HNO3) = 0.43 M HNO3
Answer:
3 Pb(NO3)2 + Al2(SO4)3 = 2 Al(NO3)3 + 3 PbSO4
Explanation:
I think your equation is incorrect? This is balanced and the sum of coefficients is 9.
Answer:
The number of protons and neutrons.
Explanation:
Neutrons and Protons can't be removed from nucleus from chemical reactions because they are held together super strong and tight. However, nuclear reactions are strong enough to separate them.
hope this helps :)
I think it might be A or D, hope I helped! Sorry if I didn't!!
