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Ksivusya [100]
3 years ago
14

2nh3(l) → nh4+(am) + nh2−(am) where (am) represents solvation by ammonia. at the boiling point (−33°c), kam = 5.1 × 10−27. calcu

late [nh4+] at this temperature.
Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0
Answer is: concentration of ammonium ions are 7,14·10⁻¹⁴ M.<span>
Chemical reaction: 2NH</span>₃(l) → NH₄⁺(am) + NH₂⁻(am).<span>
Kam = 5,1·10</span>⁻²⁷.<span>
[NH</span>₄⁺] · [NH₂⁻] = x; equilibrium concentration of cations and anions.<span>
Kam = [NH</span>₄⁺] · [NH₂⁻].<span>
Kam = x².
x = [NH</span>₄⁺] = √5,1·10⁻²⁷.<span>
[NH</span>₄⁺] = 7,14·10⁻¹⁴<span> M.</span>
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Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907
melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent.\frac{^0 C}{m}

m = molality of solute (m or \frac{mol}{Kg} )

Given : kf = 1.86 \frac{^0 C*Kg}{mol}

m = 0.907 \frac{mol}{Kg} )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 \frac{^0 C*Kg}{mol} * 0.907\frac{mol}{Kg} )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

5 0
3 years ago
As you move down a group of the periodic table how does the atomic radius of the atoms change​
lana [24]

Answer:

An atom gets larger as the number of electronic shells increase; therefore the radius of atoms increases as you go down a certain group in the periodic table of elements. In general, the size of an atom will decrease as you move from left to the right of a certain period.

Explanation:

5 0
3 years ago
Acetylene burns in air according to the following equation: C2H2(g) + 5 2 O2(g) → 2 CO2(g) + H2O(g) ΔH o rxn = −1255.8 kJ Given
professor190 [17]

Answer:  -227 kJ

Explanation:

The balanced chemical reaction is,

C_2H_2(g)+\frac{5}{2}O_2(g)\rightarrow 2CO_2(g)+H_2O(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+ n_{H_2O}\times \Delta H_{H_2O})]-[(n_{C_2H_2}\times \Delta H_{C_2H_2})+(n_{O_2}\times \Delta H_{O_2})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-1255.8=[(2\times -393.5)+(1\times -241.8)]-[(1\times \Delta H_{C_2H_2})+(\frac{5}{2}\times 0)]

-1255.8=[(-787)+(-241.8)]-[(1\times \Delta H_{C_2H_2})+(0)]

\Delta H_{C_2H_2}=-227kJ

Therefore, the enthalpy change for C_2H_2 is -227 kJ.

7 0
3 years ago
Which statement explains how the bands in the crystal of a metal are like atomic orbitals?
algol [13]
Please provide the choices here.

The similarity of the bands in the crystal of a metal to the atomic orbitals can be explained by the band theory of metals. In an atom, when the electrons get excited, the electrons jumps to a higher orbital so as to reach equilibrium. This is analogous to the electrons in the metals which also jumps to another band once excited by an external energy (e.g. electrical energy). 
3 0
3 years ago
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Does sodium (Na) and argon (Ar) on the periodic table have similar properties? Explain in terms of location on the periodic tabl
iVinArrow [24]

Sodium (Na) and Argon (Ar) on the periodic table does not have similar properties.

PERIODIC TABLE:

  • Periodic table is the organized table that showcases the position of elements. The periodic table is organized into groups and periods.

  • Groups of the periodic table is in a vertical format labeled 1 - 7 while the period is in a horizontal format labeled 1 - 7.

  • Elements in the same group have the same number of valence electrons and hence, possess similar chemical properties.

  • Sodium (Na) belongs to group 1 while argon is a noble gas, hence, they are not in the same group of the periodic table and cannot have same properties.

Learn more at: brainly.com/question/24089206?referrer=searchResults

6 0
2 years ago
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