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Ksivusya [100]
3 years ago
14

2nh3(l) → nh4+(am) + nh2−(am) where (am) represents solvation by ammonia. at the boiling point (−33°c), kam = 5.1 × 10−27. calcu

late [nh4+] at this temperature.
Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0
Answer is: concentration of ammonium ions are 7,14·10⁻¹⁴ M.<span>
Chemical reaction: 2NH</span>₃(l) → NH₄⁺(am) + NH₂⁻(am).<span>
Kam = 5,1·10</span>⁻²⁷.<span>
[NH</span>₄⁺] · [NH₂⁻] = x; equilibrium concentration of cations and anions.<span>
Kam = [NH</span>₄⁺] · [NH₂⁻].<span>
Kam = x².
x = [NH</span>₄⁺] = √5,1·10⁻²⁷.<span>
[NH</span>₄⁺] = 7,14·10⁻¹⁴<span> M.</span>
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