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GenaCL600 [577]
3 years ago
12

A robot spacecraft returned samples from the planetesimal 98765 ALEKS, located in the outer Solar System. Mass-spectroscopic ana

lysis produced the following data on the isotopes of molybdenum in these samples:
isotope mass
(amu) relative
abundance
96Mo
95.9
90.6%
95Mo
94.9
9.4%
Use these measurements to complete the entry for molybdenum in the Periodic Table that would be used on 98765 ALEKS. Be sure your answers have the correct number of significant digits.

Caution: your correct answer will have the same format but not necessarily the same numbers as the entry for molybdenum in the Periodic Table we use here on Earth.
Chemistry
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:97.8amu

Explanation:

The relative atomic mass of molybdenum is the sum of the masses of all the isotopes of molybdenum in nature.

(90.6/100 × 95.9/1) + (9.4/100 × 94.9/1) =

(0.906×95.9) + (0.094×94.9)=

86.8854+8.9206=97.8amu

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Which of the following is an inorganic compound?<br> AgNO3<br> C6H12<br> СНОН<br> C₂H7N
Lemur [1.5K]

Answer:

AgNO3

Explanation:

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Please help
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Answer:

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4 0
2 years ago
What is the boiling point of ch3ch2ch2ch3
Tasya [4]
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7 0
3 years ago
Iodine-131 half life 8.040 how long will it take for a 40 gram sample of iodine-131 to decay to 0.75 grams
otez555 [7]

Answer:

See explanation below

Explanation:

To get this, we need to apply the general expression for half life decay:

N = N₀e(-λt)    (1)

Where:

N and N₀ would be the final and innitial quantities, in this case, masses.

t: time required to decay

λ: factor related to half life

From the above expression we need λ and t. To get λ we use the following expression:

λ = t₁₂/ln2   (2)

And we have the value of half life, so, replacing we have:

λ = 8.04 / ln2 = 11.6

Now, we can replace in (1) and then, solve for t:

0.75 = 40 exp(-11.6t)

0.75 / 40 = exp(-11.6t)

ln(0.01875) = -11.6t

-3.9766 = -11.6t

t = -3.9766 / -11.6

<h2>t = 0.34 days</h2><h2></h2>
3 0
3 years ago
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