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GenaCL600 [577]
3 years ago
12

A robot spacecraft returned samples from the planetesimal 98765 ALEKS, located in the outer Solar System. Mass-spectroscopic ana

lysis produced the following data on the isotopes of molybdenum in these samples:
isotope mass
(amu) relative
abundance
96Mo
95.9
90.6%
95Mo
94.9
9.4%
Use these measurements to complete the entry for molybdenum in the Periodic Table that would be used on 98765 ALEKS. Be sure your answers have the correct number of significant digits.

Caution: your correct answer will have the same format but not necessarily the same numbers as the entry for molybdenum in the Periodic Table we use here on Earth.
Chemistry
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:97.8amu

Explanation:

The relative atomic mass of molybdenum is the sum of the masses of all the isotopes of molybdenum in nature.

(90.6/100 × 95.9/1) + (9.4/100 × 94.9/1) =

(0.906×95.9) + (0.094×94.9)=

86.8854+8.9206=97.8amu

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A 10.0 g sample of an unknown liquid is vaporized at 120.0°C and 5.0 atm. The volume of the vapour is found to be 568.0 mL. The
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Answer:

molecular formula of liquid = C₈H₁₈

Explanation:

First we determine the empirical formula of the liquid:

Number of moles of each element present in the liquid = % mass / molar mass

For Carbon, (molar mass = 12.01 g/mol) : 84.2/12.01 =7.011 moles

For Hydrogen (molar mass = 1.01 g/mol) : 15.8/1.01 = 15.643

Simplest mole ratio of the elements, C : H  is given by:

C = 7.011/7.011 = 1.0

H = 15.643/7.011 = 2.23

Multiplying through with 5, C:H = 5:11

Therefore, empirical formula is C₅H₁₁

The molecular mass of the liquid is next determined:

Using PV = nRT to find the number of moles of the liquid present

P = 5.0 atm; V = 568.0 mL = 0.568 L; R = 0.082 L*atmmol⁻¹ K⁻¹; T = 273 + 120 = 393 K

n = PV/RT = (5*0.568)/0.082*393

n = 0.088 moles

Molar mass of liquid = mass/no of moles = 10.0 g/ 0.088 moles = 113.63 gmol⁻¹

Molecular formula = n(empirical formula)

Molar mass of empirical formula, C₅H₁₁ = 71 gmol⁻¹

n = molecular mass/empirical mass = 113.63/71 = 1.6

Therefore, molecular formula =  1.6*(C₅H₁₁) = C₈H₁₈

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