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makkiz [27]
3 years ago
10

An amoeba is a one-celled protist. Amoeba contain all the organelles of a typical eukaryotic animal cell. It is a heterotroph an

d moves through an aquatic environment using cytoplasmic streaming and pseudopods What would you expect to happen FIRST if an amoeba senses prey present in its environment?
Physics
1 answer:
horrorfan [7]3 years ago
4 0

The correct answer is the amoeba will deploy its pseudopods (cytoplasmic extentions) to capture the prey and phagocyte.

The amoeba most known and probably the most representative of the kind. Large (up to 500 microns), common in stagnant waters, extremely voracious as evidenced by multiple digestive vacuoles.

Amoebae are characterized by a deformable cell body emitting changes of shape, the pseudopods, which allow them to crawl on a support or to capture microscopic prey by phagocytosis.

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Answer:

c.o Kg • ms 08

Explanation:

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7 0
3 years ago
An airplane flew 1000 m in 400 seconds. What is the airplane's speed?
weqwewe [10]

Answer:

speed =  \frac{distance}{time}  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =  \frac{1000}{400}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 2.5m {s}^{ - 1}

6 0
3 years ago
Read 2 more answers
What happens when you dip open bottle in bucket full of water?why​?<br>chapter=pressure​
Degger [83]

Answer: It goes inside filling most of it .

Explanation: This happens because the bottle is empty and the bucket is full of water.

3 0
3 years ago
25 POINTS FOR CORRECT ANSWER
castortr0y [4]
No.  I do not agree with Stefan.  Quite the contrary.  I disagree
with his description of "<span>angle of incidence" as the angle between
the surface of the mirror and the incoming ray. 

The correct description of "angle of incidence" is </span><span>the angle between
the NORMAL TO the surface of the mirror and the incoming ray. 

Thus, the true angle of incidence is the complement of the angle that
Stefan calculates or measures.</span>
5 0
3 years ago
Read 2 more answers
A 23 kg body is moving through space in the positive direction of an x axis with a speed of 130 m/s when, due to an internal exp
babymother [125]

Answer:

a) Vx = 1088m/s

b) Vy = -162.93m/s

c) 5246745J

Explanation:

Mass of unbroken body = 23kg

Its velocity along +ve X-axis = 130m/s

Mass of first broken body, m1= 9.4kg

Its velocity along +ve X-axis = 130m/s

Nass of 2nd broken body, m2 = 6.1kg

Its velocity long-lived X - axis = -550m/s

Mass of 3rd broken body = ?

m3 = (23 - 9.4 - 6.1)kg

m3 = 7.5kg

Let velocity along the x-axis = Vx

Let the velocity along the x-axis = Vy

Applying law of conservation of momentum along x-axis

a) m1×0 + m2×(-550) + m3×(Vx) =M × 130

9.4 × 0 + 6.1× (-550) + 7.5(Vx) = 23 ×130

0 + (-5170) + 7.5Vx = 2990

2990 + 5170 = 7.5Vx

8160 = 7.5Vx

Vx = 8160/7.5

Vx = 1088m/s

b) Aplying conservation of momentum along the x-axis

(m1×130) + (m2 × 0) + (m3× Vy) = 0

(9.4 × 130) + (6.1 ×550) + 7.5Vy = 0

1222 + 0 + 7.5Vy = 0

1222 = -7.5Vy

Vy = 1222/(-7.5)

Vy = -262.93m/s

c) The energy released or change in KE is given by:

1/2[(m1v1^2) + (m2v2^2) +(m3Vx^2) ]= MV^2

Change in KE = 1/2[ 9.4× 130^2 + 6.1 × 550^2 + 7.5 × 1088^2 ] - 1/2(23 × 130^2)

Change in KE = 1/2[158860 + 1845250 + 8878080] - 1/2[388700]

Change in KE = 5441095 - 194350

Change in KE = 5246745J

4 0
3 years ago
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