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erma4kov [3.2K]
3 years ago
7

An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the

runway before takeoff?
Physics
2 answers:
labwork [276]3 years ago
7 0
4
x28
==
112
I believe that is the answer.
Papessa [141]3 years ago
4 0

Answer:

1568m

Explanation:

An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before takeoff?

Motion is he change in position of an object with respect to time.

velocity:is the displacement change with respect to time

distance is

From newton's equation of motion

S=ut+1/2at^2

We assume that the airplane is starting from rest

at rest u ,initial velocity becomes 0

a, acceleration 4m/s^2

t, time=28secs

we superpose into the equation, we have

S=0*4+0.5*4*28^2

S=1568m

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All the big volcanoes are in the northern hemisphere of Mars, and most of the craters are in the southern hemisphere is of the following statements that best characterizes the surface of the planet Mars.


Hope this helps,

Davinia.

4 0
4 years ago
A wire with a linear mass density of 1.17 g/cm moves at a constant speed on a horizontal surface and the coefficient of kinetic
stira [4]

Answer:

The value is B  =  0.2312 \  T

The direction is into the surface

Explanation:

From the question we are told that

   The mass density is  \mu =\frac{m}{L}  = 1.17 \ g/cm =0.117 kg/m

   The coefficient of kinetic friction is  \mu_k  =  0.250

   The current the wire carries is  I =  1.24 \  A

Generally the magnetic force acting on the wire is mathematically represented as

         F_F   = F_B

Here   F_F is the frictional  force which is mathematically represented as

      F_F =  \mu_k *  m *  g

While F_B  is the magnetic force which is mathematically represented as

       F_B  = BILsin(\theta )

Here \theta =90^o is the angle between the direction of the force and that of the current

So

      F_B  = BIL

So

      BIL  =  \mu_k * m * g

=>   B  =  \mu_k *  \frac{m}{L} * [\frac{g}{I} ]

=>   B  =  0.25 *  0.117  * [\frac{9.8}{1.24} ]

=>   B  =  0.2312 \  T

Apply the right hand curling rule , the thumb pointing towards that direction of the current we see that the direction of the magnetic field is into the surface as shown on the first uploaded image

8 0
3 years ago
Explain why isokinetic exercises cannot generally be performed by individuals at home.
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Iso-kinetic exercises cannot be performed at home by an individual because they require specific machines that enable to exercise at a constant speed with professional guidance.

<u>Explanation :</u>

Iso-kinetic exercises are that kind of training regimes that require a constant pace to strengthen your muscles with the help of machines with significant specifications.

The machines involved in iso-kinetic exercises control your pace with variable resistance throughout the session and hence, it’s not a cup of tea for an individual to trace his/her performances and the respective improvements.

So, before going for a iso-kinetic schedule, be sure to have a word with your physiotherapist to train well with the machines under the specifications that can better suit your body and its requirements.

6 0
3 years ago
Read 2 more answers
How many cells must be connected in series to give the 350 v a large catfish can produce?
victus00 [196]
Each electrocyte can produce 110 mv.
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3 0
3 years ago
A 35 kg child goes down a playground that is inclined at an angle of 27.5 degrees above the horizontal. Find the acceleration if
tigry1 [53]

Answer:

4.16m/s²

Explanation:

According to Newtons second law;

\sum Fx = ma_x\\Fm - Ff = ma_x\\W sin\theta - \mu R cos \theta = ma_x\\mg sin\theta - \mu mg cos\theta = ma_x\\

Fm is the moving force

\mu is  the coefficient of kinetic friction between the child and the slide

m is the mass

g is the acceleration due to gravity

a is the acceleration of the child

Substitute the given values and get the acceleration as shown;

35(9.8)sin27.5 - 0.415(35)(cos27.5) = 35a

158.38-12.88 = 35a

145.49 = 35a

a = 145.49/35

a = 4.16m/s²

Hence the acceleration of the body is  4.16m/s²

4 0
3 years ago
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