(p+1) (p-1). solved this on paper . hope it helps .
Answer:
By putting the coordinates on the graph I think
Step-by-step explanation:
Answer:
exactly one, 0's, triangular matrix, product and 1.
Step-by-step explanation:
So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.
"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).
Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.
The logarithmic expression is
To expand the expression we have to use some properties of logarithm.
We know that 
By using this property we can write,
Square root means to the power 1/2, so for 
, we can write 
.
Now we have to use another property of logarithm.
We know that, 
So we will use this property to 
Now we have to use another property of logarithm.
We know that, 
By using this property we can write,
This is the required aswer here.
