A spring of negligible mass and force constant k = 430 N/m is hung vertically, and a 0.270 kg pan is suspended from its lower en
1 answer:
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<h3>Question:</h3>
How to find g (acceleration due to gravity)
<h3>Solution:</h3>We know,
Acceleration due to gravity (g)
where, G = Gravitational constant
M = Mass of the earth
R = Radius of the earth
Putting these values of G, M and R in the above formula, we get
So, the value of acceleration due to gravity is
Hope it helps.
Do comment if you have any query.
Answer:
Explanation:
Given that,
Weight of jet
W = 2.25 × 10^6 N
It is at rest on the run way.
Two rear wheels are 16m behind the front wheel
Center of gravity of plane 10.6m behind the front wheel
A. Normal force entered on the ground by front wheel.
Taking moment about the the about the real wheel.
Check attachment for better understanding
So,
Clock wise moment = anti-clockwise moment
W × 5.4 = N × 16
2.25 × 10^6 × 5.4 = 16•N
N = 2.25 × 10^6 × 5.4 / 16
N = 7.594 × 10^5 N
B. Normal force on each of the rear two wheels.
Using the second principle of equilibrium body.
Let the rear wheel normal be Nr and note, the are two real wheels, then, there will be two normal forces
ΣFy = 0
Nr + Nr + N — W = 0
2•Nr = W—N
2•Nr = 2.25 × 10^6 — 7.594 × 10^5
2•Nr = 1.491 × 10^6
Nr = 1.491 × 10^6 / 2
Nr = 7.453 × 10^5 N
