A spring of negligible mass and force constant k = 430 N/m is hung vertically, and a 0.270 kg pan is suspended from its lower en
1 answer:
You might be interested in
Answer:
a)
b)
Explanation:
The net force on the car must produce the centripetal acceleration necessary to make this circle, which is . At the top of the circle, the normal force and the weight point downwards (like the centripetal force should), while at the bottom the normal force points upwards (like the centripetal force should) and the weight downwards, so we have (taking the upwards direction as positive):
Which means:
The limit for falling off would be , so the minimum speed would be:
Answer:
0.37 m
Explanation:
The angular frequency, ω, of a loaded spring is related to the period, T, by
The maximum velocity of the oscillation occurs at the equilibrium point and is given by
A is the amplitude or maximum displacement from the equilibrium.
From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,
To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation
is the final velocity,
is the initial velocity (same as v above), a is acceleration of gravity and h is the height.
Answer:
Inverted
Real
Explanation:
u = Object distance = 30 cm
v = Image distance
f = Focal length = 10 cm
Lens Equation
As, the image distance is positive the image is real and forms on the other side of the lens
As, the magnification is negative the image is inverted
