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3 years ago

How do I love someone

Physics

1 answer:

AleksandrR [38]3 years ago

7 0

Answer:

if you need to ask this question, then u dont love them

Explanation:

give them ur whole heart and always wanna cuddle

plza mark me brainliest i need only one moreeeeee

You might be interested in

Part A-Circumference of a circle

Bezzdna [24]

The circumference of a circle with a diameter of 10 cm is 31.4cm.

The circumference of a circle is its edge or the measurement of its entire arc.

The circumference of a circle with radius $r$ is $2\pi r$ .

The circle in question has a diameter of 10 cm.

The radius of a circle's diameter is equal to its length divided by two. Consequently, the given circle's radius is 5 cm.

If we assume that π=3.14, then the given circle's circumference will be equal to 2×π×5. Consequently, 31.4 cm is the required circumference.

As a result, a circle with a diameter of 10 cm has a 31.4 cm circumference and it has been expressed in three significant figures.

Learn more about diameter here brainly.com/question/358744

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6 0

1 year ago

An ice cube is placed in a microwave oven.

Juli2301 [7.4K]

Answer:

It takes 266 seconds to melt the ice.

Explanation:

Given data

Power of the microwave oven (P): 125 Watt

Heat supplied to the ice (Q): 33,200 Joule

Time for the melting (t): to be determined

In order to determine the time required to melt the ice, we can use the following expression.

P = Q/t

t = Q / P = 33,200 J/ 125 W = 266 s

It takes 266 seconds to melt the ice.

5 0

3 years ago

A ski jumper starts at the top of a 400m high hill before skiing down to the bottom. If the ski jumper has a mass of 75kg how mu

alekssr [168]

Answer:B. 30,000 J

Explanation:

6 0

2 years ago

The magnitude of the gravitational field strength near Earth's surface is represented by

Zanzabum

Answer:

The magnitude of the gravitational field strength near Earth's surface is represented by approximately $9.82\,\frac{m}{s^{2}}$ .

Explanation:

Let be M and m the masses of the planet and a person standing on the surface of the planet, so that M >> m. The attraction force between the planet and the person is represented by the Newton's Law of Gravitation:

$F = G\cdot \frac{M\cdot m}{r^{2}}$

Where:

$M$ - Mass of the planet Earth, measured in kilograms.

$m$ - Mass of the person, measured in kilograms.

$r$ - Radius of the Earth, measured in meters.

$G$ - Gravitational constant, measured in $\frac{m^{3}}{kg\cdot s^{2}}$ .

But also, the magnitude of the gravitational field is given by the definition of weight, that is:

$F = m \cdot g$

Where:

$m$ - Mass of the person, measured in kilograms.

$g$ - Gravity constant, measured in meters per square second.

After comparing this expression with the first one, the following equivalence is found:

$g = \frac{G\cdot M}{r^{2}}$

Given that $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$ , $M = 5.972 \times 10^{24}\,kg$ and $r = 6.371 \times 10^{6}\,m$ , the magnitude of the gravitational field near Earth's surface is: