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USPshnik [31]
3 years ago
12

What is the equation for density (feel free to use go*ogle search, my parents blocked it on my computer so I can't look it up my

self)
Physics
2 answers:
12345 [234]3 years ago
6 0

Answer: The answer is right here and it is corrct

:)\rho ={\frac {m}{V}}

Explanation: I think you can unblocked it but Hope this help :)

Lostsunrise [7]3 years ago
5 0
P = m/v I’m pretty sure.
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A 9V battery is directly connected to each of 3 LED bulbs. Select the statement that accurately describes this circuit.
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where are the statements?

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It does not hit the students face because the speed of the balloon slows down as energy is lost through thermal.

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Suppose a 20-foot ladder is leaning against a building, reaching to the bottom of a second-floor window 15 feet above the ground
Papessa [141]

Answer:

The answer is β=0,85 rads

Explanation:

As the ladder is leaning against the building, we can imagine there´s a triangle where 20ft is the hypotenuse and 15ft is the maximum vertical distance between the ladder and the ground, it means, the leg opposite to β which is the angle we need

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In this case we will need to find β, this way:

betha=sin^-1((15ft/20ft))

Then β=48,6°  

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3 years ago
What is the current
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Your office has a 0.025 m^3 cylindrical container of drinking water. The radius of the container is about 13 cm. Required:a. Whe
uranmaximum [27]

Answer:

<em>a) 105935.7 Pa</em>

<em>b) 103630.35 Pa</em>

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The volume of the container = 0.025 m^3

The radius of the container = 13 cm = 0.13 m

We have to find the height of the tank

From the equation for finding the volume of the cylinder,

V = \pi r^2h

where

V is the volume of the cylinder

h is the height of the cylinder

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0.025 = 3.142 x 0.13^2 x h

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h = 0.025/0.0531 = 0.47 m

Pressure at the bottom of the tank P = ρgh

where

ρ is the density of water = 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

h is the depth of water which is equal to the height of the tank

substituting values, we have

P = 1000 x 9.81 x 0.47 = 4610.7 Pa

atmospheric pressure = 101325 Pa

therefore, the pressure in the tank bottom above atmospheric pressure = 101325 Pa + 4610.7 Pa = <em>105935.7 Pa</em>

b) For half way down the container, depth of water will be = 0.47/2 = 0.235 m

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This pressure above atmospheric pressure = 101325 Pa + 2305.35 Pa = <em>103630.35 Pa</em>

7 0
3 years ago
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