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3 years ago

12

What is the equation for density (feel free to use go*ogle search, my parents blocked it on my computer so I can't look it up my

self)

2 answers:

12345 [234]3 years ago

6 0

Answer: The answer is right here and it is corrct

:) $\rho ={\frac {m}{V}}$

Explanation: I think you can unblocked it but Hope this help :)

Lostsunrise [7]3 years ago

5 0

P = m/v I’m pretty sure.

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What affects how an object falls toward earth?

ioda

1. Air resistance (therefore, the air density, shape (aerodynamic or not), and surface area affected
2. The gravitational acceleration constant (g = 9.8 m/s^2 on Earth)

4 0

3 years ago

Read 2 more answers

Outside the space shuttle, you and a friend pull on two ropes to dock a satellite whose mass is 700 kg. The satellite is initial

MaRussiya [10]

Answer:

your friend did a work of 1717.34 J

Explanation:

The sum of the work made by your friend and you is equal the change in the kinetic energy, so:

$W_a+W_b=\frac{1}{2}mv_f^{2}-\frac{1}{2}mv_i^{2}$

Where $W_a$ is the work that you did, $W_b$ is the work that your friend did, m is the mass of the satellite and $v_f$ and $v_i$ are the final and initial speeds

Additionally the work that you did is equal to:

$W_a=F.s$

Where F and s are vectors. So, the vector s that said the displacement is calculated as:

s = <2.3, 2.6, -11.8> - <3.3, -1.6, 2.0>

s = <-1 , 4.2 , -13.8>

Therefore, $W_a$ is:

$W_a=.$

$W_a=(-400*-1)+(500*4.2)+(250*-13.8)\\W_a=400+2100-3450\\W_a=-950$

Then, replacing the values on initial equation and solving for $W_b$ , we get:

$-950+W_b=\frac{1}{2}(700)(6.18)^{2}-\frac{1}{2}(700)(6)^{2}\\-950+W_b=767.24\\W_b=767.24+950\\W_b=1717.34J$

Finally, your friend did a work of 1717.34 J

3 0

3 years ago

Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.9537 N when separated by

scoray [572]

Answer:

<em>The initial charges on the spheres are </em> $6.796\ 10^{-6}\ c$ and $-3.898\ 10^{-6}\ c$

Explanation:

<u>Electrostatic Force </u>

Two charges q1 and q2 separated a distance d exert a force on each other which magnitude is computed by the known Coulomb's formula

$\displaystyle F=\frac{K\ q_1\ q_2}{d^2}$

We are given the distance between two unknown charges d=50 cm = 0.5 m and the attractive force of -0.9537 N. This means both charges are opposite signs.

With these conditions we set the equation

$\displaystyle F_1=\frac{K\ q_1\ q_2}{0.5^2}=-0.9537$

Rearranging

$\displaystyle q_1\ q_2=\frac{-0.9537(0.5)^2}{k}$

Solving for q1.q2

$\displaystyle q_1\ q_2=-2.6492.10^{-11}\ c^2\ \ ......[1]$

The second part of the problem states the spheres are later connected by a conducting wire which is removed, and then, the spheres repel each other with an electrostatic force of 0.0756 N.

The conducting wire makes the charges on both spheres to balance, i.e. free electrons of the negative charge pass to the positive charge and they finally have the same charge:

$\displaystyle q=\frac{q_1+q_2}{2}$

Using this second condition:

$\displaystyle F_2=\frac{K\ q^2}{0.5^2}=\frac{K(q_1+q_2)^2}{(4)0.5^2}=0.0756$

$\displaystyle q_1+q_2=2.8983\ 10^{-6}\ C$

Solving for q2

$\displaystyle q_2=2.8983\ 10^{-6}\ C-q_1$

Replacing in [1]

$\displaystyle q_1(2.8983\ 10^{-6}-q_1)=-2.64917.10^{-11}$

Rearranging, we have a second-degree equation for q1.

$\displaystyle q_1^2-2.8983.10^{-6}q_1-2.64917.10^{-11}=0$

Solving, we have two possible solutions

$\displaystyle q_1=6,796.10^{-6}\ c$

$\displaystyle q_1=-3.898.10^{-6}\ c$

Which yields to two solutions for q2

$\displaystyle q_2=-3.898.10^{-6}\ c$

$\displaystyle q_2=6.796.10^{-6}\ c$

Regardless of their order, the initial charges on the spheres are $6.796\ 10^{-6}\ c$ and $-3.898\ 10^{-6}\ c$

8 0

3 years ago

A heat engine uses thermal energy flowing from a heat source that is 225k to a cold sink that is 50k. What is the approximate ef

Arte-miy333 [17]

efficiency of heat engine is given as

$\eta = 1 - \frac{T_2}{T_1}$

now we know that

$T_2$ = temperature of sink

$T_1$ = temperature of high temperature source

now it is given that

$T_2 = 50 k$

$T_1 = 225 k$

now from the given equation we have

$\eta = 1 - \frac{50}{225}$

$\eta = 0.78$

so efficiency of heat engine will be 78%

3 0

3 years ago

The Doppler Effect is caused by which of the following?

Artist 52 [7]

Answer:

the type of wave

Explanation:

Description: Doppler Effect works on both light and sound objects. For instance, when a sound object moves towards you, the frequency of the sound waves increases, leading to a higher pitch. Conversely, if it moves away from you, the frequency of the sound waves decreases and the pitch comes down.

8 0

3 years ago