Answer:
jajjsjsjddjdjdjdjdjjdjeieiririitofodoslwnridooskemridisoskswkwjj jwjwiwiwiwkiwiw
Answer:
92.87 g.
Explanation:
∵ The percentage yield = (actual yield/theoretical yield)*100.
- We need to calculate the theoretical yield:
From the balanced reaction:
<em>PCl₃ + Cl₂ → PCl₅,</em>
It is clear that 1 mol of PCl₃ reacts with 1 mol of Cl₂ to produce 1 mol of PCl₅.
- We need to calculate the no. of moles of 73.7 g PCl₃:
n = mass/molar mass = (73.7 g)/(137.33 g/mol) = 0.536 mol.
<u><em>Using cross multiplication:</em></u>
1 mol of PCl₃ produce → 1 mol of PCl₅, from stichiometry.
∴ 0.536 mol of PCl₃ produce → 0.536 mol of PCl₅.
∴ The mass of PCl₅ (theoretical yield) = (no. of moles) * (molar mass) = (0.536 mol)*(208.24 g/mol) = 111.62 g.
<em>∵ The percentage yield = (actual yield/theoretical yield)*100.</em>
The percentage yield = 83.2%, theoretical yield = 111.62 g.
∴ The actual yield of PCl₅ = (The percentage yield)(theoretical yield)/100 = (83.2%)(111.62 g)/100 = 92.87 g.
Answer is: mass od zinc is 392,28 g.
N(Zn) = 3,6·10²⁴.
n(Zn) = N(Zn) ÷ Na.
n(Zn) = 3,6·10²⁴ ÷ 6·10²³ 1/mol.
n(Zn) = 6 mol.
m(Zn) = n(Zn) · M(Zn).
m(Zn) = 6 mol · 65,38 g/mol.
m(Zn) = 392,28 g.
Na - Avogadro number.
n - amount of substance.
M - molar mass.
