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slavikrds [6]
3 years ago
8

6. what is the metric system prefix for the quantity 0.000 001? a) centi- b) deci- c) kilo- d) micro-

Chemistry
2 answers:
Sergeeva-Olga [200]3 years ago
8 0
The metric system prefix for the above quantity would be D. Micro. Which is 10^-6.
Svetllana [295]3 years ago
3 0

Answer :  The correct option is, (d) micro-

Explanation :

Metric system : The Metric System measured the things in meters, grams, liters, etc and adds prefixes like kilo, milli and centi to the count orders of the magnitude.

In metric system, a metric prefix is a unit prefix that comes before the basic unit of measure to indicate the fraction of the unit.

Metric system (factor)          Prefix            Symbol

1000                                       kilo-                  k

100                                        hecto-                h

10                                           deca-                da

0.1                                           deci-                 d

0.001                                      centi-                 c

0.0001                                    milli-                  m

0.0000001                            micro-                 μ

Hence, according to the metric system prefix the prefix used for 0.000001 is, micro-

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SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

6 0
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