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slavikrds [6]
3 years ago
8

6. what is the metric system prefix for the quantity 0.000 001? a) centi- b) deci- c) kilo- d) micro-

Chemistry
2 answers:
Sergeeva-Olga [200]3 years ago
8 0
The metric system prefix for the above quantity would be D. Micro. Which is 10^-6.
Svetllana [295]3 years ago
3 0

Answer :  The correct option is, (d) micro-

Explanation :

Metric system : The Metric System measured the things in meters, grams, liters, etc and adds prefixes like kilo, milli and centi to the count orders of the magnitude.

In metric system, a metric prefix is a unit prefix that comes before the basic unit of measure to indicate the fraction of the unit.

Metric system (factor)          Prefix            Symbol

1000                                       kilo-                  k

100                                        hecto-                h

10                                           deca-                da

0.1                                           deci-                 d

0.001                                      centi-                 c

0.0001                                    milli-                  m

0.0000001                            micro-                 μ

Hence, according to the metric system prefix the prefix used for 0.000001 is, micro-

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Answer:

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Explanation:

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At a festival, spherical balloons with a radius of 280. Cm are to be inflated with hot air and released. The air at the festival
evablogger [386]

Answer:

8608.18 balloons

Explanation:

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Data needed:

Enthalpy of propane formation: 103.85kJ / mol

Specific heat capacity of air: 1.009J · g ° C

Density of air at 100 ° C: 0.946kg / m3

Density of propane at 100 ° C: 1.440kg / m3

First we will calculate the propane heat (C3H8)

3000g * (1mol / 44g) * (103.85kJ / mol) * (1000J / 1kJ) = 7.08068 * 10 ^ 6 J

Then we can calculate the mass of the air with the heat formula

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m = Q / c delta T = (7.08068 * 10 ^ 6 J) / (1.009J / kg ° C * (100-25) ° C) =

m = 93566.96kg

We now calculate the volume of a balloon.

V = 4/3 * pi * r ^ 3 = 4/3 * 3.14 * 1.4m ^ 3 = 11.49m ^ 3

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The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int
bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

\epsilon = Molar absorption coefficient

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I_o = incident light

I = transmitted light

Given :

l = 1 cm, c = 1 mg/mL ,\epsilon = 15,000 M^{-1}cm^{-1}

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

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A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm

A=0.8426 \approx 0.84

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

5 0
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