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OverLord2011 [107]
3 years ago
15

Skill and

Chemistry
1 answer:
Leokris [45]3 years ago
5 0

Answer:

2.5 m/s

Explanation:

total of 12 meters in 30 seconds

12x2.5=30

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Bromine, a liquid at room temperature has a boiling point of 58 degrees celsius and a melting point at -7.2 degree celsius bromi
ra1l [238]

Hello!


Bromine can be classified as a pure substance.


Why?


Bromine is an element with atomic number 35 on group 17 of the Periodic Table. That's the first sign that shows us that it is a pure substance.


But the fact that it has a clear and defined boiling and melting point is a sign that we are in the presence of a pure substance. Pure substances are characterized by defined boiling and melting points.


Mixtures usually have a range of temperatures in which they melt and boil.


Have a nice day!

8 0
4 years ago
A gas occupies a volume of 40.0 milliliters at 20 c if the volume is increased too 80.0 milliliters at constant pressure, the re
Troyanec [42]
Charles law gives the relationship between temperature and volume of gases. It  states that the volume of gas is directly proportional to temperature at constant pressure. 
V / T = k 
where V - volume and T - temperature in Kelvin and k - constant 
\frac{V1}{T1} =  \frac{V2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - 20 °C + 273 = 293 K
substituting these values in the equation 
\frac{40.0 mL}{293 K}  =  \frac{80.0 mL}{T}
T = 586 K
temperature in celsius = 586 K - 273 = 313 °C
new temperature is 313 °C
8 0
4 years ago
What is the mRNA for TTGACAAGTTAC
sertanlavr [38]

Answer:

What is the question? I don't understand what you are trying to say.

3 0
3 years ago
So2+o2 = so3 método de tanteo​
gulaghasi [49]

Answer:

I dont understand

Explanation:

818191919

7 0
3 years ago
A 49.48-mL sample of an ammonia solution is analyzed by titration with HCl. It took 38.73 mL of 0.0952 M HCl to titrate the ammo
Kryger [21]

Answer:

M₂ = 0.0745 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = 0.0952 M

V₁ = 38.73 mL

M₂ = ?

V₂ = 49.48 mL

Using the above formula , the molarity of ammonia , can be calculated as ,

M₁V₁ = M₂V₂  

0.0952 M * 38.73 mL = M₂* 49.48 mL

M₂ = 0.0745 M

8 0
3 years ago
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