Answer:
The induced voltage in the Secondary is 18 volt.
Explanation:
Given that,
Voltage = 120 volt
Number of turns in primary = 500
Number of turns in secondary = 75
We need to calculate the induced voltage in the Secondary
Using relation number of turns and voltage in primary and secondary
![\dfrac{V_{p}}{V_{s}}=\dfrac{N_{p}}{N_{s}}](https://tex.z-dn.net/?f=%5Cdfrac%7BV_%7Bp%7D%7D%7BV_%7Bs%7D%7D%3D%5Cdfrac%7BN_%7Bp%7D%7D%7BN_%7Bs%7D%7D)
Where,
= Number of primary coil
= Number of secondary coil
= Voltage of primary coil
= Voltage of primary coil
Put the value into the formula
![\dfrac{120}{V_{s}}=\dfrac{500}{75}](https://tex.z-dn.net/?f=%5Cdfrac%7B120%7D%7BV_%7Bs%7D%7D%3D%5Cdfrac%7B500%7D%7B75%7D)
![V_{s}=\dfrac{120\times75}{500}](https://tex.z-dn.net/?f=V_%7Bs%7D%3D%5Cdfrac%7B120%5Ctimes75%7D%7B500%7D)
![V_{s}=18\ Volt](https://tex.z-dn.net/?f=V_%7Bs%7D%3D18%5C%20Volt)
Hence, The induced voltage in the Secondary is 18 volt.
Answer:
nope
Explanation:
sige bigyan kitang Happy pills
The total work done is
<span>W=60 plus 120
=180J
For the graphs please find the attached image</span>
Answer:
The velocity is ![v =2.455 \ m/s](https://tex.z-dn.net/?f=v%20%3D2.455%20%5C%20%20m%2Fs)
Explanation:
From the question we are told that
The diameter of the pipe is ![d = 4.25 \ cm = 0.0425 \ m](https://tex.z-dn.net/?f=d%20%3D%20%204.25%20%5C%20cm%20%20%3D%200.0425%20%5C%20m)
The magnetic field is ![B = 0.575 \ T](https://tex.z-dn.net/?f=B%20%20%3D%20%200.575%20%5C%20%20T)
The hall voltage is ![V_H = 60.0 mV = 60 *10^{-3} \ V](https://tex.z-dn.net/?f=V_H%20%3D%20%2060.0%20mV%20%20%3D%20%2060%20%2A10%5E%7B-3%7D%20%5C%20%20V)
Generally the average fluid velocity is mathematically represented as
![v = \frac{V}{ B * d }](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7BV%7D%7B%20B%20%20%2A%20%20d%20%7D)
=> ![v = \frac{60*10^{-3}}{ 0.575 * 0.0425 }](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B60%2A10%5E%7B-3%7D%7D%7B%200.575%20%20%20%2A%20%200.0425%20%20%7D)
=> ![v =2.455 \ m/s](https://tex.z-dn.net/?f=v%20%3D2.455%20%5C%20%20m%2Fs)