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Aleksandr-060686 [28]
3 years ago
14

Please help me to solve this, I don’t really know what to do.

Physics
1 answer:
zalisa [80]3 years ago
5 0

Explanation:

Use Ohm's Law

V / R = I

I = 5A

V = 110V

R =?

Solve for R

if you need further help let me know

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How to measure the speed of sound in air?
Leona [35]

STEP ONE:


Let  you and your friend stand as far away as possible from a large reflecting wall and clap your hands rapidly at a regular rate.  


STEP TWO:


Adjust this rate until each clap just coincides with the return of an echo of its predecessor, or until clap and echo are heard as equally spaced.


STEP THREE:


Use a stopwatch to find the time between claps, t. Make a rough measurement of distance to the wall, s. Thus the speed of sound, v = 2s/t

8 0
3 years ago
so I know you can solve this either by using Vox or Voy. I'm getting 3.08s when using Vox and 3.14s for Voy way. For Voy I'm usi
Tatiana [17]

The person's horizontal position is given by

x=v_0\cos40^\circ t

and the time it takes for him to travel 56.6 m is

56.6\,\mathrm m=\left(24.0\,\dfrac{\mathrm m}{\mathrm s}\right)\cos40^\circ t\implies t=3.08\,\mathrm s

so your first computed time is the correct one.

The question requires a bit of careful reading, and I think there may be a mistake in the problem. The person's vertical velocity v_y at time t is

v_y=v_{0y}-gt

which tells us that he would reach the ground at about t=3.15\,\mathrm s. In this time, he would have traveled

x=v_{0x}(3.15\,\mathrm s)=57.9\,\mathrm m

But we're told that he is caught by a net at 56.6 m, which would mean that the net cannot have been placed at the same height from which he was launched. However, it's possible that the moment at which he was launched doesn't refer to the moment the cannon went off, but rather the moment at which the person left the muzzle of the cannon a fraction of a second after the cannon was set off. After this time, the person's initial vertical velocity v_{0y} would have been a bit smaller than \left(24.0\,\frac{\mathrm m}{\mathrm s}\right)\sin40^\circ.

7 0
3 years ago
HELP!!! ASP EASY QUESTION! WILL GIVE BRAINEST IF U ANSWER!
Harlamova29_29 [7]
I believe the answer is Anther.
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5 0
3 years ago
Imagine that there is a small rocky body caught by Earth’s gravity. Draw a comic-strip cartoon
vladimir1956 [14]

To create this comic strip you can use a narration describing each step and illustrate each one with one image or drawing.

Creating a comic strip involves using images and short texts to explain a specific idea or phenomenon. In the case of the process for a meteor to enter Earth you can use the following ideas.

  • A meteoroid approaches the Earth at high speed and draw a meteor traveling near to different planets and approaching Earth.
  • What is that? and draw the Earth wondering who or what is approaching.
  • The meteoroid enters the atmosphere of the Earth and becomes a meteor and draw the rocky body burning
  • The rocky body crashes with the surface becoming a meteorite and draw the zone where the meteorite crashed.

Learn more about comic in: brainly.com/question/1418309

6 0
2 years ago
A car with a total mass of 1800 kg (including passengers) is driving down a washboard road with bumps spaced 4.9 m apart. The ri
Drupady [299]

Answer:

k = 9.6 x 10^5 N/m or 9.6 kN/m

Explanation:

First, we need to use the expression to calculate the spring constant which is:

w² = k/m

Solving for k:

k = w²*m

To get the angular velocity:

w = 2πf

The problem is giving the linear velocity of the car which is 5.7 m/s. With this we can calculate the frequency of the car:

f = V/x

f = 5.7 / 4.9 = 1.16 Hz

Now the angular velocity:

w = 2π*1.16

w = 7.29 rad/s

Finally, solving for k:

k = (7.29)² * 1800

k = 95,659.38 N/m

In two significant figures it'll ve 9.6 kN/m

5 0
3 years ago
Read 2 more answers
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