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3 years ago

Coulomb’s law is similar to what other law in physics?

Physics

2 answers:

Gemiola [76]3 years ago

6 0

Universal law of gravitation

vlada-n [284]3 years ago

5 0

Answer:

Universal Law of Gravitation

Explanation:

Coulomb’s law explains the magnitude of force between two charges separated by a distance.

$F=\frac{kq_{1}q_{2} }{r^{2} }$

Universal Law of Gravitation. explains the magnitude of force between two masses separated by a distance.

$F=\frac{Gm_{1}m_{2} }{r^{2} }$

Newton’s second Law explains the relationship between force and acceleration

$F = ma$

Snell’s Law explains the relationship between the angles of incidence and refraction and the refractive indices of two refractive medium when light passes from one medium to another at a angle

$n_{1} sin\theta _{1} =n_{2} sin\theta _{2}$

Law of Conservation of Energy explains how energy can neither be created nor be destroyed.

So Coulomb’s law , Universal Law of Gravitation and Newton’s second Law all give us the magnitude of force but only the columb's law and the universal law of gravitation are the Inverse Square Law.

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If the resistivity of copper is less than that of gold at room temperature, which of the following statements must be true? Gold

KiRa [710]

Answer:

Gold Has A Higher Resistance Than Copper. The Sample Of Gold Is Thinner Than The Sample Of Copper. Electrons In Gold Are More Likely To Be Scattered Than Electrons In Copper At Room Temperature When they are exelerated by the same electric field.

Explanation:

5 0

3 years ago

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s in 10.0 s. At th

Arte-miy333 [17]

Answer:

22 revolutions

Explanation:

2 rev/s = 2*(2π rad/rev) = 12.57 rad/s

The angular acceleration when it starting

$\alpha_a = \frac{\Delta \omega}{\Delta t} = \frac{12.57}{10} = 1.257 rad/s^2$

The angular acceleration when it stopping:

$\alpha_o = \frac{\Delta \omega}{\Delta t} = \frac{-12.57}{12} = -1.05 rad/s^2$

The angular distance it covers when starting from rest:

$\omega^2 - 0^2 = 2\alpha_a\theta_a$

$\theta_a = \frac{\omega^2}{2\alpha_a} = \frac{12.57^2}{2*1.257} = 62.8 rad$

The angular distance it covers when coming to complete stop:

$0 - \omega^2 = 2\alpha_o\theta_o$

$\theta_o = \frac{-\omega^2}{2\alpha_o} = \frac{-12.57^2}{2*(-1.05)} = 75.4 rad$

So the total angular distance it covers within 22 s is 62.8 + 75.4 = 138.23 rad or 138.23 / (2π) = 22 revolutions

6 0

3 years ago

A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.4 m/s, a typical raindrop speed. How fast

kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$