1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lerok [7]
3 years ago
8

Two students are simultaneously pushing a glider on a frictionless air track, each with a constant horizontal force. In the exam

ples that follow, assume that student 1 always does positive work on the block (Ws, > 0 and that student 2 always does negative work (Ws2 0 Suppose that the glider moves to the left with constant speed. 1. In which direction is each student pushing the block? Use the definition of work to answer
Physics
1 answer:
Gala2k [10]3 years ago
4 0

Answer:

<em>The student 1 pushes to the left, the student 2 pushed to the right</em>

Explanation:

<u>Mechanical Work</u>

The work done by a force F on an object moving a distance X and making an angle \theta with the force is given by

W=F.X.cos\theta

If the force and the distance point in the same direction, the angle is 0 and the work is positive.

If the force and the distance point in opposite directions, the angle is 180° and the work is negative.

We know the glider moves to the left and the student 1 always does positive work, thus he must be pushing the block to the left to have the same direction.

The same can be applied to the second student who does a negative work when the block goes to the left, so he must be pushing to the right direction.

Summary: The student 1 pushes to the left, the student 2 pushed to the right

You might be interested in
1. The current in a wire is 0.72A. Calculate the charge that passes through the wire in; a. 4 s b. 60 s c. 180 s d. 7 s e. 0.5 s
Vlad [161]
Let current be I, charge be Q and time be t.
Here we are provided with,
I = 0.72A
t = 4s / 60s / 180s / 7s / 0.5s
We know,
I = Q/t

Case I
---------
When, t = 4s
0.72 = Q/4
Q = 0.72 * 4 = 2.88C

Case II
----------
When, t = 60s
0.72 = Q/60
Q = 0.72 * 60 = 43.2C

Case III
-----------
When, t = 180s
0.72 = Q/180
Q = 0.72 * 180 = 129.6C

Case IV
-----------
When, t = 7s
0.72 = Q/7
Q = 0.72 * 7 = 5.04C

Case V
----------
When, t = 0.5s
0.72 = Q/0.5
Q = 0.72 * 0.5 = 0.36C
6 0
3 years ago
The acceleration due to gravity on the moon is about 1/6 of the acceleration due to gravity on the earth. A net force F acts hor
uysha [10]

Answer:

c.a_m

Explanation:

We are given that

Acceleration due to gravity on the moon=a_m

Acceleration due to gravity on the earth=a_e

g_m=\frac{1}{6}g_e

Net force due to am on an object on moon=F_{net}=ma_m

There is no friction and no drag force and there is no gravity involved

Then, the force acting on an object on earth=F=ma_e

F=F_{net}(given)

ma_m=ma_e

a_e=a_m

Hence, option c is true.

3 0
3 years ago
Select the appropriate units for each property of a wave.
IceJOKER [234]

Intensity: Decibels

Amplitude: Meters

Frequency: Hertz

<u>Explanation:</u>

The Wave is not visible to eyes and they can easily propagate through vacuum. the average power travelling at a given period of time in a space is the intensity. Decibels is the measure of intensity. it is measured in the decibel scale. The wave's strength and the intensity gives the amplitude of wave. It is measured using meters.

The wave's amplitude and the energy has a direct proportionality.  The number occurrence of wave cycles per second refers to the frequency of wave. it is measured in hertz. it is also measured as the number of cycles that occurs per second.

4 0
3 years ago
A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 5.64 10-2 kg/s. the density of the gasoline is 735
Irina18 [472]
Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m

Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²

Let v =  speed of pumping the gasoline, m/s
Then the mass flow rate is 
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s

The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s

Answer:  2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
7 0
3 years ago
Read 2 more answers
Help again please !!!
rusak2 [61]
D I think .... don’t be mad if I’m wrong
5 0
3 years ago
Other questions:
  • When water vapor is cooled it three forms into water droplets why does this represent a conservation in mass
    10·1 answer
  • 8. A person with a mass of 15 kg is walking on a flat surface at a velocity of 5 m/s. What is the walker's momentum?
    5·1 answer
  • What is the name of the process that describes the decrease in frequency
    7·1 answer
  • You are driving at 90 km/h. How many meters are you covering per second?
    12·1 answer
  • A lab technician needs to clean medical instruments that have been exposed to bacteria. Which electromagnetic wave would be most
    6·2 answers
  • Consider the equation S + O2 → SO2. What type of reaction is this? a. synthesis b. decomposition c. single displacement d. doubl
    6·2 answers
  • Students are using a mallet to hit a drum. The diagram below shows this action.
    7·2 answers
  • A portion size is always equivalent to the serving size listed on the label. A. True B. False
    7·1 answer
  • A car is accelerating to the right. In which direction is the applied force?
    6·1 answer
  • A train moving at 5 m/sec passed a track gang and then accelerated uniformly a rate of 1.2 m/sec/sec for 5 min. How far did the
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!