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Lerok [7]
3 years ago
8

Two students are simultaneously pushing a glider on a frictionless air track, each with a constant horizontal force. In the exam

ples that follow, assume that student 1 always does positive work on the block (Ws, > 0 and that student 2 always does negative work (Ws2 0 Suppose that the glider moves to the left with constant speed. 1. In which direction is each student pushing the block? Use the definition of work to answer
Physics
1 answer:
Gala2k [10]3 years ago
4 0

Answer:

<em>The student 1 pushes to the left, the student 2 pushed to the right</em>

Explanation:

<u>Mechanical Work</u>

The work done by a force F on an object moving a distance X and making an angle \theta with the force is given by

W=F.X.cos\theta

If the force and the distance point in the same direction, the angle is 0 and the work is positive.

If the force and the distance point in opposite directions, the angle is 180° and the work is negative.

We know the glider moves to the left and the student 1 always does positive work, thus he must be pushing the block to the left to have the same direction.

The same can be applied to the second student who does a negative work when the block goes to the left, so he must be pushing to the right direction.

Summary: The student 1 pushes to the left, the student 2 pushed to the right

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A person in a kayak starts paddling, and it accelerates from 0 to 0.680 m/s in a distance of 0.428 m. If the combined mass of th
d1i1m1o1n [39]

Answer:

Net force, F = 44.66 N

Explanation:

It is given by,

Initial velocity of the person, u = 0

Final velocity of the person, v = 0.68 m/s

Distance, s = 0.428 m

Combined mass of the person and the kayak, m = 82.7 kg

We need to find the net force acting on the kayak i.e.

F = ma...........(1)

Firstly, we will calculate the value of "a" from third equation of motion as :

v^2-u^2=2as

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{(0.68\ m/s)^2-0}{2\times 0.428\ m}

a=0.54\ m/s^2

Put the value of a in equation (1) as :

F=82.7\ kg\times 0.54\ m/s^2

F = 44.66 N

So, the net force acting on the kayak is 44.66 N. Hence, this is the required solution.

6 0
3 years ago
Two identical resistors are connected first in series and second in parallel. The equivalent resistances of the two types of con
trasher [3.6K]

Answer:

\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2

Explanation:

We have series and parallel combination of two resisters R_{1} and R_{2}.

Series combination is

R_{s}= R_{1}+R_{2} and Parallel is R_{p} = (\frac{1}{R_{1}}+\frac{1}{R_{2}}  )^-1

Now dividing series equivalent resistance by parallel resistance gives us

\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2.

Note! series Combination is simply superposition of two elements (resisters in this case ) in a circuit.

4 0
2 years ago
A ball has a mass of 2 kg and is thrown with a force of 8 Newtons for .35 seconds. What is the ball's change in
Anna [14]

Answer:

1.4s

Explanation:

Given parameters:

Mass of ball  = 2kg

Force  = 8N

Time  = 0.35s

Unknown:

Change in velocity  = ?

Solution:

To solve this problem, we use the expression obtained from Newton's second law of motion which is shown below:

      Ft  = m(v  - u)

 So;

         Ft  = m Δv

F is the force

t is the time

m is the mass

Δv is the change in velocity

             8 x 0.35  = 2 x Δv

                  Δv  = 1.4s

6 0
2 years ago
One earth day equals 24 hours.
Artyom0805 [142]

Answer:

Correct, is there another part to the question?

7 0
3 years ago
Read 2 more answers
Little Tammy lines up to tackle Jackson to (unsuccessfully) prove the law of conservation of momentum. Tammy’s mass is 34.0 kg a
Leya [2.2K]

Answer:

So Tammy must move with speed 4.76 m/s in opposite direction of Jackson

Explanation:

As per law of conservation of momentum we know that there is no external force on it

So here we can say that initial momentum of the system must be equal to the final momentum of the system

now we have

m_1v_1 + m_2v_2 = 0

final they both comes to rest so here we can say that final momentum must be zero

now we have

34 v + 54 (3 m/s) = 0

v = -4.76 m/s

6 0
3 years ago
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