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Lerok [7]
3 years ago
8

Two students are simultaneously pushing a glider on a frictionless air track, each with a constant horizontal force. In the exam

ples that follow, assume that student 1 always does positive work on the block (Ws, > 0 and that student 2 always does negative work (Ws2 0 Suppose that the glider moves to the left with constant speed. 1. In which direction is each student pushing the block? Use the definition of work to answer
Physics
1 answer:
Gala2k [10]3 years ago
4 0

Answer:

<em>The student 1 pushes to the left, the student 2 pushed to the right</em>

Explanation:

<u>Mechanical Work</u>

The work done by a force F on an object moving a distance X and making an angle \theta with the force is given by

W=F.X.cos\theta

If the force and the distance point in the same direction, the angle is 0 and the work is positive.

If the force and the distance point in opposite directions, the angle is 180° and the work is negative.

We know the glider moves to the left and the student 1 always does positive work, thus he must be pushing the block to the left to have the same direction.

The same can be applied to the second student who does a negative work when the block goes to the left, so he must be pushing to the right direction.

Summary: The student 1 pushes to the left, the student 2 pushed to the right

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Answer:

The frictional force needed to overcome the cart is 4.83N

Explanation:

The frictional force can be obtained using the following formula:

F= \mu R

where \mu is the coefficient of friction = 0.02

R = Normal reaction of the load = mgcos\theta = 25 \times 9.81 \times cos 10 = 241.52N

Now that we have the necessary parameters that we can place into the equation, we can now go ahead and make our substitutions, to get the value of F.

F=0.02 \times 241.52N

F = 4.83 N

Hence, the frictional force needed to overcome the cart is 4.83N

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3 years ago
The density of lead is 30.2g/cm^3.what is the value in kilograms per meter cube?
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11300 kgm3

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The answer is A. C and O..

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Describe the differences among ultraviolet waves, visible light waves, and infrared waves. how are these waves alike?
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Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He travels at a steady 45.0 mph . Beth leaves Los A
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a.Beth

b.2232 s

Explanation:

We are given that

Distance,d=400 mi

Speed of Alan,v=45 mph

Speed of Beth,v'=55 mph

a.Time =\frac{distance}{speed}

Using the formula

Time taken by Alan=\frac{400}{45}=8.89 hr

Time taken by Beth=\frac{400}{55}=7.27hr

Alan will reach San Francisco at 4:53 PM

Beth will reach San Francisco at 4:16 PM

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b.Difference between time=8.89-7.27=1.62 hr

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