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Evgen [1.6K]
3 years ago
13

High friction materials​

Physics
1 answer:
Harrizon [31]3 years ago
7 0

Answer:

For the dry and static friction materials, some of these are Rubber, Aluminum, Gold, Platinum,

Explanation:

High friction materials has higher coefficient of friction (COF).

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Which celestial body would have the strongest gravitational pull on a satellite orbiting 100 km above its surface? Explain your
Andreyy89

Answer:

Jupiter

Explanation:

Since the mass of Jupiter is the greatest from the given choices, it will exert the most force on any object orbiting 100km above its surface.

This is compliance with the Newton's law of universal gravitation which states that "the force of attraction between two bodies is directly proportional to the magnitude of their masses and inversely proportional to the distances between them".

  • Therefore, the more the masses of two bodies, the higher the gravitational attraction
  • Since the distance is the same, the planet with the greater mass will exert the most force on the satellite.
3 0
3 years ago
Read 2 more answers
a bus moving at speed of 25m/s beginning to slow at rate 4m/s^2each second how long does it take to stop​
Paladinen [302]

Explanation:

Initial velocity is 25m/s i.e. u. Final velocity would be zero since the bus stopped. It is noted that the bus deccelartion of 4m/s, so the acceleration should be considered negative of 4m/s I.e. 4m/s. So using third law of motion i.e.

v^2 - u^2= 2as

(0)^2 - (25)^2= -2×4×s {Note here I used minus sign in acceleration}

-625 = -8×s

s=625 ÷ 8

s= 125 m

So bus would cover a distance of 125m before coming to rest.

3 0
3 years ago
a man can swim in still water with speed of 2kmhr-1 wants to cross a river 200m wide flowing with 1kmhr-1 . Calculate the time t
tangare [24]

Answer:

d savage

Explanation:

3 0
3 years ago
Newton’s third law is the law of
matrenka [14]

Answer:

B. interactive

Explanation:

newtons first law is inertia his second is acceleration and third is interactive.

6 0
3 years ago
Read 2 more answers
Two motorcyclists are riding side-by-side at night and the distance between their center-mounted headlights is 1.40 m. (a) If th
dezoksy [38]

Answer:

θ = 1.591 10⁻² rad

Explanation:

For this exercise we must suppose a criterion when two light sources are considered separated, we use the most common criterion the Rayleigh criterion that establishes that two light sources are separated census the central maximum of one of them coincides with the first minimum of the other source

         

Let's write the diffraction equation for a slit

       a sin θ = m λ

The first minimum occurs for m = 1, also field in these we experience the angles are very small, we can approximate the sin θ = θ

             θ = λ / a

In our case, the pupil is circular, so the system must be solved in polar coordinates, so a numerical constant is introduced.

           θ = 1.22 λ / D

Where D is the diameter of the pupil

 Let's apply this equation to our case

        θ = 1.22 600 10⁻⁹ / 0.460 10⁻²

        θ = 1.591 10⁻² rad

This is the angle separation to solve the two light sources

6 0
3 years ago
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