This is true.
The reaction rates are affected by how often the particles collide.
Answer is: electron in 2pz orbital.
The principal quantum number is one
of four quantum numbers which are assigned to each electron in
an atom to describe that electron's state, n=1,2,3... n=2 - <span>the </span>second energy level.<span>
The azimuthal quantum number is a quantum number for
an atomic orbital that determines its orbital angular
momentum and describes the shape of the orbital. l = 0,1...n-1, when l = 1, that is p </span>subshell.
The magnetic quantum number<span>, </span><span>ml, show</span> orbital<span> in which the electron is located, ml = -l...+l, ml = 0 is pz orbital.</span>
The spin quantum number<span>, </span><span>ms</span><span>, is the spin of the electron; ms = +1/2 or -1/2.</span>
132 g of C , 22 g of H , 176 g of O
132 + 22 + 176 => 330 g <span>of the substance
</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u H = 1.0 u O = 16.0 u
C = 132 / 12.0 => 11 moles
H = 22 / 1.0 => 22 moles
O = 176 / 16.0 => 11 moles
Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1
H = 22 / 11 => 2
O = 11 / 11 => 1
formula empirically <span>is : CH</span>₂O
hope this helps!
Answer:
Explanation:
The melting point of a substance is the temperature at which its melt. The state of a substance is dependent on it's melting temperature. Generally, melting point above 25 °C is a solid.
This means phenol is a solid
Duodecane has melting point below 25 °C hence it is either a liquid or gas. However its boiling point of 216 °C means it would require higher temperature to boil it. Since 25 °C is less than 216 °C it means that it would remain in the liquid state.
Methane has melting point below 25 °C hence it is either a liquid or gas. However its boiling point of -164 °C means it boils easily even at very low temperatures. Since 25 °C is greater than -164 °C it means that it would exist in the gaseous state
