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Maru [420]
2 years ago
8

Which is the correct way to write 602,200,000,000,000,000,000,000 in scientific notation?

Chemistry
2 answers:
alisha [4.7K]2 years ago
7 0
<span>The correct way to write 602,200,000,000,000,000,000,000 in scientific notation is 6.202 x 10^23. In the scientific notation, the number is written as a multiplication of a number from 1 to 9 and 10 raised to the adequate power. 602,200,000,000,000,000,000,000 = 6.202 x 100,000,000,000,000,000,000,000. Since 10 = 10^1; 100 = 10^2; 1,000 = 10^3, etc. then 100,000,000,000,000,000,000,000 = 10^23. Therefore, 602,200,000,000,000,000,000,000 = 6.202 x 100,000,000,000,000,000,000,000 = 6.202 x 10^23.</span>
worty [1.4K]2 years ago
6 0

Answer : The correct way is, 6.022\times 10^{23}

Explanation :

Scientific notation : It is defined as the representation of expressing the number that are too big or too small that is written in the decimal form. That means always written in the power of 10 form.

For example : 5000 is written as, 5\times 10^3

As we are given that the value is, 602,200,000,000,000,000,000,000

This number is written in scientific notation as :

6.022\times 10^{23}

Therefore, the correct way to write the given number is, 6.022\times 10^{23}

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algol13

Answer:4

Explanation:To balance the equation you need to make the number of each element equivalent in both sides.

To start add a 2 in front of the MnO2 which balances the Mn.

Then balance the oxygen by adding a 4 in front of H20.

The H then needs a 8 as it’s coefficient.

7 0
1 year ago
Write a net ionic equation that describes a slightly basic solution resulting from dissolving nac2h3o2 in water. Identify all of
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Answer: The net ionic equation will be as follows.

     CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)

Explanation:

The chemical equation for the given reaction is as follows.

      CH_{3}COONa(aq) + H_{2}O(l) \rightleftarrow CH_{3}COOH(aq) + NaOH(aq)

We know that a strong acid or base will dissociate completely into a solvent whereas a weak acid or base dissociates partially into the solvent. Hence, the ionic equation will be as follows.  

CH_{3}COO^{-}(aq) + Na^{+}(aq) H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + Na^{+}(aq) + OH^{-}(aq) Now, we will cancel the spectator ions from the above equation. Therefore, the net ionic equation will be as follows.

     CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)

or,  C_{2}H_{3}O^{-}_{2}(aq) + H_{2}O(l) \rightleftharpoons HC_{2}H_{3}O_{2}(aq) + OH^{-}(aq)

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The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.

In an ideal gas the equation has been given as:

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