Answer:
2-butanone = 72.11 g/mol (option F)
Propyl acetate = 102.13 g/mol (option C)
4-methyl-2-pentanone = 100.16 g/mol (option D)
Butyl acetate = 116.16 g/mol (option B)
Methanol = 32.04 g/mol (option E)
Ethanol = 46.07 g/mol (option A)
Explanation:
Step 1: Data given
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol
Step 2:
2-butanone = C4H8O
⇒ 4*12.01 + 8*1.01 + 16.00 = 72.11 g/mol (option F)
Propyl acetate = C5H10O2
⇒ 5*12.01 + 10*1.01 + 2*16.00 = 102.13 g/mol (option C)
4-methyl-2-pentanone = C6H12O
⇒ 6*12.01 + 12*1.01 + 16.00 = 100.16 g/mol (option D)
Butyl acetate = C6H12O2
⇒ 6*12.01 + 12*1.01 + 2*16.00 = 116.16 g/mol (option B)
Methanol = CH3OH = CH4O
⇒ 12.01 + 4*1.01 + 16.00 = 32.04 g/mol (option E)
Ethanol = C2H5OH = C2H6O
⇒ 2*12.01 + 6*1.01 + 16.00 = 46.07 g/mol (option A)
