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Mila [183]
4 years ago
11

When a compound, such as salt, dissolves in water, it's said to be:

Physics
2 answers:
Lilit [14]4 years ago
5 0

Answer:D:soluble

Explanation:

when a compound such as salt dissolves in water it is said to be soluble

MARK AS BRAINLIEST

uranmaximum [27]4 years ago
5 0
The answer is D. Soluble
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Is a football tackle an elastic or inelastic collision and why?
QveST [7]

If the kinetic energy of an object changes, then the collision is considered inelastic. This is regardless of whether the objects sticks together or not.

My best answer for this question would be D) inelastic, because kinetic energy is not conserved.

We can tell from the collision that it is not elastic.

Momentum is is conserved, it transfers to the other player.

Kinetic energy is not conserved, at it turns into internal friction.

I hope this helps! :)

3 0
3 years ago
As you drive in your car at 22.5 mi/h, you see a child’s ball roll into the street ahead of you. You hit the brakes and stop as
evablogger [386]

Answer:

Explanation:

Speed of car =22.5miles/hr

U=22.5miles/hour

Applied brake and come to rest

Final velocity, =0

t, =2sec

Given that,

Speed=distance /time

Then,

Distance, =speed, ×time

Converting mile/hour to m/s

Given that

Use: 1 mile= 1600 m, 1 h= 3600s

22.5miles/hour × 1600m/mile × 1hour/3600s

Therefore, 22.5mile/hour=10m/s

Using speed =10m/s

Distance =speed ×time

Distance=10×2

Distance, =20m

The distance travelled before coming to rest is 20m.

5 0
3 years ago
When is the magnitude of the acceleration of a mass on a spring at its maximum value?
DiKsa [7]

Answer:

D

Explanation:

Now we know that Force is the rate of change of momentum meaning

F= mv/t

But

mv/t = Ke

v/t = ke/m

a= ke/m

Where a is acceleration

K is constant of proportionality of tension on a spring

e is the extension substended by a string.

From the formula of acceleration we can see that as mass decreases acceleration increases so we can see that m = 1

We would have a maximum value of acceleration.

6 0
4 years ago
A 1.40-kg block is on a frictionless, 30 ∘ inclined plane. The block is attached to a spring (k = 40.0 N/m ) that is fixed to a
Oliga [24]

Answer:

the mass drop by 6.5cm before coming to rest.

Explanation:

Given that:

the mass of the block M= 1.40 kg

angle of inclination θ = 30°

spring constant K = 40.0 N/m

mass of the suspended block m = 60.0 g = 0.06 kg

initial downward speed = 1.40 m/s

The objective is to determine how far does it drop before coming to rest?

Let assume it drops at y from a certain point in the vertical direction;

Then :

Workdone by gravity on the mass of the block is:

w_1g = 1.4*9.81*y*sin30 = - 6.867y

Workdone by gravity on the mass of the suspended block is:

w_2g = 0.06*9.81 = 0.5886

The workdone by the spring = -1/2ky²

= -0.5 × 40y²

= -20 y²

The net workdone is = -20 y² - 6.867y + 0.5886y

According to the work energy theorem

Net work done = Δ K.E

-20 y² - 6.867y + 0.5886 = 1/2 × 0.06 × 1.4²

-20 y²  - 6.867y + 0.5886 = 0.5 × 0.1176

-20 y²  - 6.867y + 0.5886 = 0.0588

-20 y²  - 6.867y + 0.5886 - 0.0588

-20 y²  - 6.867y + 0.5298 = 0

multiplying through by (-)

20 y²  + 6.867y - 0.5298 = 0

Using the quadratic formula:

\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}

where;

a = 20 ; b = 6.867 c= - 0.5298

\dfrac{-(6.867)  \pm \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)}

= \dfrac{-(6.867)  + \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)} \ \ \ OR \ \ \  \dfrac{-(6.867)  - \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)}= 0.0649 OR  −0.408

We go by the positive integer

y = 0.0649 m

y = 6.5 cm

Therefore; the mass drop by 6.5cm before coming to rest.

7 0
4 years ago
Which describes the average velocity of an ant traveling at a constant speed
yanalaym [24]

Answer: A. The total displacement divided by the time and  C. The slope of the ant's displacement vs. time graph.

Explanation:

Hi! The question seems incomplete, but I found the options on the internt:

A. The total displacement divided by the time.

B. The slope of the ant's acceleration vs. time graph.

C. The slope of the ant's displacement vs. time graph.

D. The average acceleration divided by the time.

Now, since we know the ant is travelling at a constant speed, its average velocity V will be expressed by the following equation:

V=\frac{d}{t}

Where:

d is the ant's total displacement

t is the time it took to the ant to travel to the kitchen

Hence one of the correct options is: A. The total displacement divided by the time

On the other hand, this can be expressed by a displacement vs. time graph graph, where the slope of that line leads to the equation written above. So, the other correct option is: C. The slope of the ant's displacement vs. time graph.

3 0
3 years ago
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