The shorter the wavelength of a photon, the greater its energy. We can see photons with wavelengths between 700 nanometers (red)
and 400 nanometers (violet), which correspond to energies of 1.8 to 3.1 electron volts (eV). Which photon energies make up the spectrum of hydrogen?
1 answer:
Answer: from 0.66 eV to 13 eV
Explanation: In order to justify this range of energy corresponding to the spectrum of hydrogen we firrsly have to consider the model given by Planck to describe this kind of atoms. On the hand the spectral series resume the main atomic transtitions corresponding for the hydrogen.
The attached file gives more details about these considerations.
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Answer:
(a) The energy of the photon is 1.632 x J.
(b) The wavelength of the photon is 1.2 x m.
(c) The frequency of the photon is 2.47 x Hz.
Explanation:
Let;
= -13.60 ev
= -3.40 ev
(a) Energy of the emitted photon can be determined as;
-
= -3.40 - (-13.60)
= -3.40 + 13.60
= 10.20 eV
= 10.20(1.6 x )
-
= 1.632 x
Joules
The energy of the emitted photon is 10.20 eV (or 1.632 x Joules).
(b) The wavelength, λ, can be determined as;
E = (hc)/ λ
where: E is the energy of the photon, h is the Planck's constant (6.6 x Js), c is the speed of light (3 x
m/s) and λ is the wavelength.
10.20(1.6 x ) = (6.6 x
* 3 x
)/ λ
λ =
= 1.213 x
Wavelength of the photon is 1.2 x m.
(c) The frequency can be determined by;
E = hf
where f is the frequency of the photon.
1.632 x = 6.6 x
x f
f =
= 2.47 x Hz
Frequency of the emitted photon is 2.47 x Hz.