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3 years ago

What is the energy of motion.

Physics

2 answers:

weqwewe [10]3 years ago

5 0

Answer: Kinetic Energy

Explanation:

AlladinOne [14]3 years ago

4 0

Answer:

Is the sum of potential and kinetic energy in an object that is used to do work.

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RUDIKE [14]

Inelastic would be the answer to this question

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3 years ago

1. Phát biểu và viết biểu thức nguyên lý I nhiệt động học, giải thích các ký hiệu.

Alisiya [41]

Answer:

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2 years ago

What type on msd causes inflammation of the tendons that correct bones to muscles

svp [43]

I believe it would be Tendonitis

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4 years ago

Two vehicles, a car and a truck, leave an intersection at the same time. The car heads east at an average speed of 20 miles pe

leva [86]

Answer:

$d = 10\times t\sqrt{29}miles$

Explanation:

Given:

't' hour be the time taken for travel by both the vehicles and 'd' be the distance between then

then

Distance traveled by the car = 20 × t miles

and

Distance traveled by the truck = 50 × t miles

now, using the Pythagoras theorem

$d = \sqrt{(20t)^2+(50t)^2}$

$d = \sqrt{400t^2+2500t^2}$

$d = \sqrt{2900t^2}$

$d = 10\times t\sqrt{29}$

thus, the equation relating the distance 'd' with the time 't' comes as

$d = 10\times t\sqrt{29}miles$

7 0

3 years ago

Prove law of conservation of energy for a stone moving vertically down ( explain energy at B & C )

STALIN [3.7K]

As per given condition of point B we can see that height at point B is "h/2" from the ground

So we know that potential energy is given as

U = mgh

so here we have to put height h = h/2

so potential energy is U = mgh/2

now for kinetic energy we need to find the speed of it after falling the distance h/2

now by kinematics we will have

$v_f^2 - 0^2 = 2(g)(h/2)$

now for kinetic energy

$KE = \frac{1}{2}mv^2 = \frac{1}{2}m(gh)$

$KE = 1/2mgh$

now total energy will be given as

$E = mgh/2 + mgh/2 = mgh$

now for point C we can say that it is the point near to ground

So here height is ZERO

now potential energy will also be zero

U = 0

now for kinetic energy we need to find speed

$v^2 - 0^2 = 2(g)(h)$

now kinetic energy

$KE = \frac{1}{2}mv^2 = \frac{1}{2}m(2gh)$

$KE = mgh$

now again we have total energy

$E = 0 + mgh = mgh$

6 0

4 years ago