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iren2701 [21]
4 years ago
8

A cameraman sitting near the open door of a news helicopter accidentally drops his 140-g mobile phone out

Physics
2 answers:
Debora [2.8K]4 years ago
6 0

Answer:

140m/s

Explanation:

Given parameters:

Mass of mobile phone  = 140g

Altitude  = 990m

Unknown:

Final velocity   = ?

Solution:

This is a motion problem. It is solvable by using the right motion equation. For this problem, understand that the phone is dropping under the influence of gravity.

      V²   =  U²  +  2gH

where V is the final velocity

           U is the initial velocity

           g is the acceleration due to gravity

          H is the height of fall

Initial velocity is 0

Input the variables;

      V²   = 0²   +  2(9.8)(990)

       V  = 139.29m/s = 140m/s

Agata [3.3K]4 years ago
4 0

Answer:B.140 m/s

Explanation:

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A swimming pool has the shape of a right circular cylinder with radius 21 feet and height 10 feet. Suppose that the pool is full
AysviL [449]

Answer:

The water required to pump all the water to a platform 2 feet above the top of the pool is  is 6061310.32 foot-pound.

Explanation:

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A=\pi r^2

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A=\pi\times21^2

A=441\pi\ feet^2

Thickness of slice t=\Delta h\ ft

The volume is,

V=(441\pi\times\Delta h)\ ft^3

We need to calculate the force

Using formula of force

F=W\times V

Where, W = water weight

V = volume

Put the value into the formula

F=62.5\times(441\pi\times\Delta h)

F=27562.5\pi\times\Delta h\ lbs

We need to calculate the work done

Using formula of work done

W=F\times d

Put the value into the formula

W=27562.5\pi\times\Delta h\times(10-h)\ ft\ lbs

We do this by integrating from h = 0 to h = 10

We need to find the total work,

Using formula of work done

W=\int_{0}^{h}{W}

Put the value into the formula

W=\int_{0}^{10}{27562.5\pi\\times(10-h)}dh

W=27562.5\pi(10h-\dfrac{h^2}{2})_{0}^{10}

W=27562.5\pi(10\times10-\dfrac{100}{2}-0)

W=4329507.37572

To pump 2 feet above platform, then each slice has to be lifted an extra 2 feet,

So, the total distance to lift slice is (12-h) instead of of 10-h

We need to calculate the water required to pump all the water to a platform 2 feet above the top of the pool

Using formula of work done

W=\int_{0}^{h}{W}

Put the value into the formula

W=\int_{0}^{10}{27562.5\pi\\times(12-h)}dh

W=27562.5\pi(12h-\dfrac{h^2}{2})_{0}^{10}

W=27562.5\pi(12\times10-\dfrac{100}{2}-0)

W=1929375\pi

W=6061310.32\ foot- pound

Hence, The water required to pump all the water to a platform 2 feet above the top of the pool is  is 6061310.32 foot-pound.

8 0
3 years ago
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