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NemiM [27]
2 years ago
6

A metallic conductor has a resistivity of 35 × 10 −6 Ω⋅m. What is the resistance of a piece that is 20 m long and has a uniform

cross-sectional area of 4.0 × 10 −6 m 2?
Physics
1 answer:
Nitella [24]2 years ago
3 0

Answer:

Therefore the resistance of the conductor is 175Ω

Explanation:

Resistance:

  • Resistance of a metallic conductor is directly proportional to its length(l).
  • Resistance of a metallic conductor is inversely proportional to its cross section area(A).

The notation sign of resistance is R.

The unit of resistance is ohm (Ω).

Therefore,

R \propto l

and

R \propto \frac{1}{A}

\therefore R\propto \frac{l}{A}

\Rightarrow R=\rho \frac{l}{A}

ρ is the proportional constant.

It is also known as resistivity of that metal.

Given ρ=35×10⁻⁶Ω-m

l= 20 m

A= 4.0×10⁻⁶m²

\therefore R=35\times 10^{-6}\times \frac{20}{4.0\times 10^{-6}}

       =175Ω

Therefore the resistance of the conductor is 175Ω

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Five kg of water is contained in a piston–cylinder assembly, initially at 5 bar and 360°C. The water is slowly heated at constan
ohaa [14]

Answer:

Explanation:

Given that,

Mass = 5kg of water

Initial pressure P•i = 5bar = 500 kPa

Pressure is constant P = 5bar

Initial temperature T•i = 360°C

Heat transferred Q = 2660 KJ

Kinetic and potential energy are negligible

a. Final volume

The initial enthalpy and specific volume can be determine from the steam table.

h•1 = 3188.83 KJ/kg

v•1 = 0.5796 m³/kg.

So, we can calculate the final enthalpy by using

Q = m(h2—h•1)

2660 = 5 (h2—3188.83)

2660/5 = h2—3188.83

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h2 = 520 + 3188.83

h2 = 3720.83 KJ/kg.

Using steam table, we can determine the final temperature and final specific volume

T•f = 608°C

v•f = 0.8115 m³/kg

Then, specific volume = volume /mass

v•f = v2/m

v2 = vf × m

v2 = 0.8115 × 5

v2 = 4.0575m³

b. Workdone?

W = m•P•(vf —vi)

W = 5 × 500(0.8115 — 0.5796)

W = 579.75 KJ

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