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Ilia_Sergeevich [38]
2 years ago
7

A rubbit gets down from a rump which its /\x=0.85m in 0.5s, The rubbit's mass is 2kg, what is the net Force?

Physics
1 answer:
mestny [16]2 years ago
8 0

Answer: 13.6 N

Explanation:

The equation of motion for the rabbit is:

\Delta x=V_{ox}t+\frac{1}{2}a_{x}t^{2} (1)

Where:

\Delta x=0.85 m is the distance traveled by the rabbit

V_{ox}=0 m/s is the rabbit's initial velocity, assuming it started from rest

t=0.5 s is the time

a_{x} is the acceleration

Isolating a_{x}:

a_{x}=\frac{2 \Delta x}{t^{2}} (2)

a_{x}=\frac{2 (0.85 m)}{(0.5)^{2}} (3)

a_{x}=6.8 m/s^{2} (4)

On the other hand, the force F_{x} is given by:

F_{x}=m.a_{x} (5)

Where m=2 kg is the mass of the rabbit

Substituting (4) in (5):

F_{x}=(2 kg)(6.8 m/s^{2}) (6)

Finally:

F_{x}=13.6 N

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