Answer:
V_vap = 161.2 L
Explanation:
The total mass of the aluminum rod is given as;
m = ρ∙V = ρ∙L∙A
Where;
ρ is density = 2700 kg/m³
L is length = 3.3m
A is cross sectional area = 3.8 cm² = 3.8 x 10⁻⁴ m²
Thus;
m = 2700kg/m³•3.3m•3.8 × 10⁻⁴m²
= 3.3858kg
By cooling down the submerged half of the aluminum rod releases an heat amount of
Q = (1/2)∙m∙cp∙∆T
Where;
cp is specific heat of aluminum aluminum = 900 J/kg
∆T is change in temperature = 274 - 4.2 = 269.8 K
Thus;
Q = (1/2)•3.3858•900•(269.8)
= 411069.978 J
The liquid absorbs this heat and vaporizes partially, such that the heat equals vaporized mass times latent heat of vaporization:
Q = m_vap•∆h_vap
Making m_vap the subject;
m_vap∙ = Q/∆h_vap
Where ∆h_vap is latent heat of vaporization given as 20900J/kg
Thus,
m_vap∙ = 411069.978/20900
= 19.668 kg
Let's divide this mass by the density of liquid helium and we get the liquid volume which has vaporized:
V_vap∙= m_vap/ρ
V_vap∙ = 19.668/122
V_vap∙ = 0.1612 m³
Converting to litres;
V_vap = 0.1612 x 1000
V_vap = 161.2 L
V or total voltage is 6 volts because when multiple power supplies of the same voltage are connected in parallel, the applied voltage is same and the current equally divides between the number of power sources.
Divide I(t) or total current 0.25 amps between the two power sources.
Is=I(t)/Ns
Is=0.25amps/2sources
Is=.125amps
Voltage is the difference in electrical potential between two points.
Current is just the rate of flow of electric charge.
Each power source supplies .125amps of current to the load
To know more about voltage,
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A.how much power is needed to push the box at a speed of.
Answer:
X=32152
Explanation:
Given that
Mean ,μ=40,839 miles
Standard deviation,σ = 4,056 miles
We know that
Given that
When P= 0.02 then Z=-2.053 (From standard chart)
X=32512.032 ≅32512
X=32152
so the guaranteed mileage is X=32152