Answer: The time required for the impluse passing through each other is approximately 0.18seconds
Explanation:
Given:
Length,L = 50m
M/L = 0.020kg/m
FA = 5.7×10^2N
FB = 2.5×10^2N
The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.
Ca(t) + CB(t) = 50
Where CA and CB are the velocities of the wire A and B
t = 50/ (CA + CB)
But C = Sqrt(FL/M)
Substituting gives:
t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))
t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))
t = 50 / (168.62 + 111.83)
t = 50/280.15
t = 0.18 seconds
B. wind.
Sun (solar) --> plants (photosynthesis) --> cola (chemical) --> heat (combustion) --> steam --> turbine (kinetic) --> generator (electric)
There is no wind.
The answer is tropical rainforest
Protons, neutrons, and electrons<span> are the three main subatomic particles found in an atom. Protons have a</span>positive<span> (+) </span>charge<span>. An easy way to remember this is to remember that both proton and </span>positive<span> start with the</span>letter<span> "</span>P<span>." Neutrons have no electrical </span>charge<span>.</span>
Answer:
The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.
Explanation:
Kinetic energy is defined as energy possessed by an object due to its motion.It is calculated by:
Kinetic energy of the 5 kg object.
Mass of object,m = 5 kg
Velocity of an object = v
Kinetic energy of the 20 kg object.
Mass of object,m' = 20 kg
Velocity of an object = v'
The ratio of the kinetic energy of the 5 kilogram object to the kinetic energy of the 20-kilogram object:
Given that, v = 2v'
The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.
