3 years ago

Time: distance: direction:velocity

Physics

1 answer:

juin [17]3 years ago

7 0

Do you want the formula?

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As air pressure decreases, what happens

Naya [18.7K]

Answer:

I believe it is B, not 100% sure though

Explanation:

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2 years ago

A 0.500-kg stone is moving in a vertical circular path attached to a string that is 75.0 cm long. The stone is moving around the

Semenov [28]

Answer:

B. 7.07 m/s

Explanation:

The velocity of the stone when it leaves the circular path is its tangential velocity, $v$ , which is given by

$v=\omega r$

where $\omega$ is the angular speed and $r$ is the radius of the circular path.

$\omega$ is given by

$\omega = 2\pi f$

where $f$ is the frequency of revolution.

Thus

$v=2\pi fr$

Using values from the question,

$v=2\pi\times 1.50\times0.75$

<em>Note the conversion of 75 cm to 0.75 m</em>

$v=2\times3.14\times 1.50\times0.75 = 9.42\times0.75 = 7.065=7.07$

6 0

3 years ago

A bead slides without friction around a loopthe-loop. The bead is released from a height 21.9 m from the bottom of the loop-the-

wariber [46]

Answer:

Part a)

$v = 12.45 m/s$

Part B)

$F_n = 0.05 N$

Explanation:

Part A)

As we know that the point A lies on the top of the loop

so we will have by energy conservation

$mgH = \frac{1}{2}mv^2 + mg(2R)$

so the speed at point A is given as

$mg(H - 2R) = \frac{1}{2}mv^2$

$v = \sqrt{2g(H - 2R)}$

$v = \sqrt{2(9.81)(21.9 - 2\times 7)}$

$v = 12.45 m/s$

Part B)

Now the force equation at point A is given as

$F_n + mg = \frac{mv^2}{R}$

$F_n = \frac{mv^2}{R} - mg$ [/tex]

$F_n = 0.004(\frac{12.45^2}{7} - 9.81)$

$F_n = 0.05 N$

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3 years ago

If i want an thrilling job witch should i chose im stuck beetween,

MA_775_DIABLO [31]

Answer:

1. horse rider

Explanation:

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3 years ago

Problem I Marcella (see warmup problem, above) gets her car moving steadily at 4m/s but suddenly someone stops ahead to assist h

Nady [450]

Answer:

Explanation:

a) KE = (1/2) * m * ( $v^{2}$ ) = F * d = 14m * 200N = 2800 m/N or 2.8 * $10^{3}$ m/N

b) 0J and 0m/s (if Marcella stopped after going 14 meters)

c) Known from part (a) that KE = 2800 J = F1 * d1,

2800J = F1 * (14m - 1m) => F1 = 2800J/13m = 215.384 N

3 0

3 years ago