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Juli2301 [7.4K]
3 years ago
6

PLEASE HELP NOW :)Temperature and salinity both influence the movement of water in deep water currents. What is the best descrip

tion of ocean water at the poles? A. cold and high salinity B.warm and high salinity C. warm and low salinity D.cold and low salinity
Chemistry
2 answers:
Ierofanga [76]3 years ago
7 0
A. I just took the test and got it right.
kenny6666 [7]3 years ago
4 0
D.....................................................
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Which of the following choices is an <br> example of gathering evidence
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Answer: Taking measurements

Explanation:

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3 years ago
Determine the concentration of a solution prepared by diluting 25.0 ml of a stock 0.188 m sr(no3)2 solution to 150.0 ml
o-na [289]
We can use the following equation to calculate the concentration of diluted solution.
c1v1 = c2v2 
where c1 is concentration and v1 is volume of stock solution, which is the more concentrated solution.
c2 is concentration and v2 is the volume of diluted solution.
substituting the values in the equation,
0.188 M x 25.0 mL = c2 x 150.0 mL 
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8 0
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your science teacher hands you a small container filled with an unknown liquid substance. he asks you to measure the mass of the
koban [17]
 we are asked in this problem to determine the mass of a liquid in a small container. In order to determine the mass, we use an analytical balance for greater accuracy by first weighing the whole system (liquid+beaker). Then transfer the liquid to another container and completely dry the beaker (wash and dry). measure the weight of the beaker. The mass of the liquid is equal to the mass of the system minus the mass of the beaker. 
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Give six examples of complex compounds.
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Answer:

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3 0
4 years ago
Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

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The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


4 0
3 years ago
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