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Sati [7]
2 years ago
5

Darwin called this idea of certain traits being selected in order for an organism to reproduce sexual selection. In crickets and

frogs, males call to attract mates and females are attracted to superior males by characteristics of their calls. How can this also be a disadvantage to survival of the species? A) Only the superior male traits are passed to the next generation. B) Female choice for mating reflects only the genes of the superior males. C) Calling can be hazardous because it also attracts parasites and predators. D) Inferior males intercept the females from the superior males and mate anyway.
Chemistry
2 answers:
tamaranim1 [39]2 years ago
7 0

Th correct answer is option C. Calling can be hazardous because it also attracts parasites and predators.

The mating call is used by the males to attract females for sexual reproduction. By using vocal sounds males are not only making themselves attractive to females, they are also making themselves vulnerable to predators.

Thus the mating call can have a disastrous effect on the survival of the species.

gogolik [260]2 years ago
5 0

Answer: C.

Calling can be hazardous because it also attracts parasites and predators.

Explanation:

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The strong Base with a pH of 12 is reduced by 4 units upon being added with solution Y. If you added a strong acid to the strong base, all ions are present in the solution, yes? So every OH- is neutralised by every H+ for example, meaning the resultant pH should be 7. The resultant pH is only 8 however, so solution Y must be a <em>weak acid </em>only!

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3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
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Answer:

a. 4,00L

b. 16,00L

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Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

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